QCAA Biology Alternative Sequence Homeostasis
11 sample questions with marking guides and sample answers
Homeostatic negative feedback mechanisms result in
a decrease in the variable being regulated.
an unfavourable or damaging effect on the body.
equilibrium among body cells and interstitial fluids.
the maintenance of a variable within a set range of values.
Reveal Answer
a decrease in the variable being regulated.
Negative feedback opposes the initial change in a variable. If the variable drops below the set point, the mechanism will increase it, so it does not always result in a decrease.
an unfavourable or damaging effect on the body.
Negative feedback mechanisms are essential for survival and health; they protect the body by maintaining stable internal conditions rather than causing damage.
equilibrium among body cells and interstitial fluids.
Homeostasis maintains a dynamic steady state, which often requires continuous energy expenditure to keep concentrations different between compartments, rather than a true chemical or physical equilibrium.
the maintenance of a variable within a set range of values.
The primary function of negative feedback is to counteract deviations from a target value, thereby keeping physiological variables within a narrow, optimal range.
Specialised cells in the arteries cause an increase in the respiratory rate when blood oxygen levels fall.
Identify the type of receptor involved in this process.
nociceptor
chemoreceptor
thermoreceptor
mechanoreceptor
Reveal Answer
nociceptor
Nociceptors are sensory receptors that detect pain or tissue damage, not chemical changes in the blood.
chemoreceptor
Chemoreceptors, specifically those in the carotid and aortic bodies, detect changes in blood chemical composition (like decreased oxygen or increased carbon dioxide) and signal the brain to adjust the respiratory rate.
thermoreceptor
Thermoreceptors are specialized to detect changes in temperature, not the concentration of gases in the blood.
mechanoreceptor
Mechanoreceptors detect physical or mechanical changes such as pressure, stretch, or vibration, rather than chemical concentrations like blood oxygen levels.
Describe how signal transduction alters cellular activity.
Reveal Answer
A signal molecule binds to its receptor on the surface of a cell, activating it. This causes a change to the protein attached to the receptor, which then activates a secondary messenger system inside the cell. These activated molecules then act on target proteins, increasing or decreasing normal cellular processes.
| Descriptor | Marks |
|---|---|
identifies that a signal molecule binds to its receptor and activates it | 1 |
describes how receptor activates proteins inside the cell | 1 |
describes how activated proteins change cell processes/composition | 1 |
Hormones are transported to target cells through
nervous system.
excretory system.
endocrine system.
circulatory system.
Reveal Answer
nervous system.
The nervous system transmits signals via electrical impulses and neurotransmitters, rather than transporting hormones throughout the body.
excretory system.
The excretory system is responsible for removing waste products from the body, not for transporting signaling molecules like hormones.
endocrine system.
While the endocrine system produces and secretes hormones, it does not have its own transport network and relies on the bloodstream for distribution.
circulatory system.
Endocrine glands secrete hormones directly into the bloodstream, allowing the circulatory system to transport them to distant target cells.
A physiological adaptation that maintains body heat in endotherms is
insulation.
hibernation.
kleptothermy.
thermogenesis.
Reveal Answer
insulation.
Insulation, such as fur, feathers, or blubber, is considered a structural or anatomical adaptation rather than a physiological process.
hibernation.
Hibernation involves a deliberate drop in body temperature and metabolic rate to conserve energy, rather than actively maintaining normal body heat.
kleptothermy.
Kleptothermy is a behavioral adaptation where an animal shares or steals body heat from another organism, not a physiological process.
thermogenesis.
Thermogenesis is a physiological process, such as shivering or brown fat metabolism, where an endotherm actively generates internal heat to maintain its body temperature.
Osmoregulation strategies include
excreting highly concentrated urine.
increasing exoskeleton permeability.
reabsorbing uric acid from kidney nephrons.
maintaining an internal environment isotonic to the external environment.
Reveal Answer
excreting highly concentrated urine.
Excreting highly concentrated urine allows an organism to eliminate waste while conserving water, which is a key osmoregulatory strategy in dehydrating environments.
increasing exoskeleton permeability.
Increasing exoskeleton permeability would lead to greater water loss, which is counterproductive to maintaining water balance.
reabsorbing uric acid from kidney nephrons.
Uric acid is a nitrogenous waste product that is actively secreted and excreted to remove nitrogen from the body, not reabsorbed for osmoregulation.
maintaining an internal environment isotonic to the external environment.
Maintaining an internal environment isotonic to the external environment is the strategy of an osmoconformer, whereas osmoregulators actively maintain an internal osmolarity different from their surroundings.
Identify two structural features of xerophyte leaves that help to maintain water balance.
Reveal Answer
Smaller surface area of leaves, sunken stomata.
| Descriptor | Marks |
|---|---|
identifies a relevant feature | 1 |
identifies a second relevant feature | 1 |
Explain why water conservation is so important for xerophytes. For each structural feature identified in Question 25a), identify the role that feature plays in water balance.
Reveal Answer
Xerophytes are plants found in dry and hot environments that consequently need to conserve water or increase water intake.
Smaller surface area of leaves reduces surface area for water evaporation, reducing water loss.
Sunken stomata increases humidity around the opening, reducing evaporation.
| Descriptor | Marks |
|---|---|
identifies the nature of the environment xerophytes inhabit | 1 |
identifies that these plants need to conserve water or increase water intake | 1 |
explains how one of the identified features helps to maintain water balance or intake | 1 |
explains how the second identified feature helps to maintain water balance or intake | 1 |
The table shows stomatal density in plants with different habitat preferences.
| Stomatal density (number of stomata/mm) | ||||
|---|---|---|---|---|
| Habitat | Temperature | Annual rainfall | Topside of leaf | Underside of leaf |
| Rainforest | Hot | High | 46.5 | 112.3 |
| Desert | Hot | Low | 42.7 | 44.4 |
Compare the stomatal density of rainforest plants and desert plants.
Reveal Answer
Plants that grow in rainforests and deserts have a similar stomatal density on the topside of the leaf. However, the stomatal density is very different on the underside of the leaf, with rainforest plants having higher stomatal density (at 112.3 stomata/mm²) while desert plants are much lower (at 44.4 stomata/mm²). This is significant because the number of stomata on the underside of the leaf affects the transpiration rate and therefore survival of plants in areas with low rainfall.
| Descriptor | Marks |
|---|---|
Identifies a similarity | 1 |
Identifies a difference | 1 |
Identifies the significance | 1 |
In the transmission of an action potential along a neuron, depolarisation occurs because
a stimulus is received that closes voltage-gated channels.
the membrane is impermeable to sodium and potassium ions.
sodium ions rush into the cell, rapidly increasing the membrane potential.
the change in membrane potential is not enough to reach threshold potential.
Reveal Answer
a stimulus is received that closes voltage-gated channels.
Depolarization is initiated when a stimulus opens voltage-gated sodium channels, rather than closing them.
the membrane is impermeable to sodium and potassium ions.
During depolarization, the membrane actually becomes highly permeable to sodium ions (), allowing them to cross the membrane.
sodium ions rush into the cell, rapidly increasing the membrane potential.
Voltage-gated sodium channels open at the threshold, allowing positively charged ions to flood the neuron and rapidly increase the membrane potential.
the change in membrane potential is not enough to reach threshold potential.
If the threshold potential is not reached, the all-or-none principle dictates that an action potential and its subsequent depolarization phase will not occur.
Identify which substance is lost by transpiration through stomata.
oxygen
nitrogen
water vapour
carbon dioxide
Reveal Answer
oxygen
While oxygen is released through stomata as a byproduct of photosynthesis, the specific term transpiration refers to the loss of water, not oxygen.
nitrogen
Plants absorb nitrogen from the soil through their roots in the form of nitrates or ammonium; they do not lose it as a gas through their stomata.
water vapour
Transpiration is the specific biological process by which water is drawn up through a plant and evaporates as water vapour, primarily through the stomata on leaves.
carbon dioxide
Carbon dioxide is primarily taken in through the stomata for photosynthesis. While it can be released during cellular respiration, this gas exchange is not called transpiration.
The table shows a comparison of the quantities of water and solutes in the glomerular filtrate of the kidney and the urine over 24 hours.
| Glomerular filtrate | Urine | |
|---|---|---|
| Water (L) | 170 | 1.5 |
| Glucose (g) | 170 | 0 |
| Sodium (g) | 560 | 5 |
| Urea (g) | 51 | 30 |
Explain how selective reabsorption and secretion across nephron membranes contribute to the urine's composition. Reference the data in your response.
Reveal Answer
Most of the water, glucose and sodium is reabsorbed and not excreted in urine, whereas most of the urea is excreted. Sodium is actively reabsorbed from glomerular filtrate to create a concentration gradient. As a result, only 5 g out of 560 g of sodium is excreted.
Water is reabsorbed out of the glomerular filtrate due to the concentration gradient created by the removal of sodium. The table shows that only 1.5 L of water is excreted from a total of 170 L of filtrate.
Nearly half of the urea is reabsorbed during water reabsorption. Of the original 51 g of urea, only 30 g is excreted, and 21 g reabsorbed. There is no glucose present in the urea as all 170 g of glucose is selectively reabsorbed and transported out of filtrate back to the blood via facilitated transport.
| Descriptor | Marks |
|---|---|
Explains the trends in the data | 1 |
Explains active sodium reabsorption | 1 |
Identifies that water reabsorption is due to sodium (salt) concentration gradient | 1 |
Identifies small amount of urea reabsorption with water | 1 |
Explains how glucose is selectively reabsorbed via facilitated transport | 1 |
If urine output for an adult decreases to an average of 30 mL/h, they are most likely dehydrated. Explain the homeostatic mechanisms that regulate the volume of urine produced during dehydration.
Reveal Answer
Antidiuretic hormone (ADH) stimulates water reabsorption by activating the insertion of water channels into kidney tubule membranes.
These channels transport solute-free water through tubular cells and back into blood, leading to a decrease in urine volume and therefore an increase in urine osmolarity.
| Descriptor | Marks |
|---|---|
Explains the role ADH plays in stimulating water channels | 1 |
Identifies that water is transported back to blood or interstitial fluid | 1 |
Identifies increased urine concentration (osmolarity) | 1 |