VCAA Physics How are fields used in electricity generation?
15 sample questions with marking guides and sample answers
Denzil is using a demonstration hand-cranked generator.
A schematic diagram of the generator is shown in Figure 17. The generator contains a rectangular coil with side lengths of 5.0 cm and 2.5 cm, consisting of 20 turns of insulated copper wire. The coil is rotated between two bar magnets that provide a field strength of 0.60 T between the magnets.
Denzil rotates the coil at a frequency of 50 Hz.
State why the flux through the coil changes as the coil rotates.
Reveal Answer
The flux through the coil is determined by the angle between the plane of the coil and the magnetic field.
| Descriptor | Marks |
|---|---|
States that the angle or orientation between the plane of the coil and the magnetic field changes | 1 |
Show that the change in flux as the coil rotates from a horizontal to a vertical position is .
Reveal Answer
| Descriptor | Marks |
|---|---|
Demonstrates correct substitution into the magnetic flux formula (e.g., ) | 1 |
Calculate the average EMF induced as the coil is rotated through a quarter turn from a horizontal to a vertical position.
Reveal Answer
| Descriptor | Marks |
|---|---|
Calculates the correct time for a quarter turn () | 1 |
Substitutes values correctly into Faraday's law formula () | 1 |
Calculates the correct average EMF of | 1 |
State a change to the set-up in Figure 17 that could produce a DC output from the generator. Give a reason for your choice.
Reveal Answer
Replace the slip rings with a split-ring commutator. The split-ring commutator will reverse the connections to the loop every half turn to ensure a DC output.
| Descriptor | Marks |
|---|---|
Identifies replacing the slip rings with a split-ring commutator | 1 |
Explains that the split-ring commutator reverses the connections to the loop every half turn to ensure a DC output | 1 |
The generator of an electrical power plant delivers to external transmission lines when operating at . The generator's voltage is stepped up to for transmission and stepped down to away (for domestic use). The overhead transmission lines have a total resistance of . Assume that all transformers are ideal.
Explain why the voltage is stepped up for transmission along the overhead transmission lines.
Reveal Answer
Students were required to identify that stepping up the voltage allowed the current to be reduced while maintaining constant power. The reason for reducing the current is that the power lost is related to the transmission current by: .
| Descriptor | Marks |
|---|---|
Identifies that stepping up the voltage allows the current to be reduced while maintaining constant power | 1 |
Relates the reduced current to a reduction in power lost during transmission () | 1 |
Calculate the current in the overhead transmission lines. Show your working.
Reveal Answer
| Descriptor | Marks |
|---|---|
Correct substitution into | 1 |
Correct final answer of or | 1 |
Determine the maximum power available for domestic use at . Show all your working.
Reveal Answer
This solution has two steps. The first is to calculate the power lost:
This was then subtracted from the power delivered by the generator:
| Descriptor | Marks |
|---|---|
Calculates the power lost in the lines () | 1 |
Subtracts the power lost from the total power delivered by the generator | 1 |
Calculates the correct available power () | 1 |
A rectangular coil of 3000 turns and dimensions is rotated in a uniform magnetic field of 2 mT.
Calculate the minimum number of revolutions per second required to produce an average EMF of 6 V.
1
3
13
50
Reveal Answer
1
This rotation speed is too slow. Using the formula , a frequency of would only produce an average EMF of .
3
This value is insufficient. Substituting into the average EMF equation yields approximately , which is less than the required .
13
The average EMF for a rotating coil is . Solving for frequency: . The closest integer option is 13.
50
This frequency is too high. At , the generated average EMF would be , far exceeding the required .
An RMS current of 15.6 A is equivalent to a peak-to-peak current of
11.0 A
22.1 A
44.1 A
55.2 A
Reveal Answer
11.0 A
Incorrect. This value is obtained by dividing the RMS current by , which does not give the peak-to-peak current.
22.1 A
Incorrect. This is the peak current (), but the question asks for the peak-to-peak current, which is twice this value.
44.1 A
Correct. The peak-to-peak current is times the RMS current. Calculating gives approximately .
55.2 A
Incorrect. This value does not correspond to the correct conversion factor of needed to find the peak-to-peak current from the RMS current.
A magnet is passed through a solenoid comprising five turns and a cross-sectional area of to produce an EMF of 0.75 V.
Calculate the EMF if the same magnet passes through another solenoid with three times as many turns and half the cross-sectional area at the same rate.
0.89 V
1.1 V
4.0 V
4.5 V
Reveal Answer
0.89 V
This value is incorrect. It does not reflect the proportional relationship where EMF scales with the product of the number of turns and the cross-sectional area.
1.1 V
According to Faraday's Law, induced EMF is proportional to both the number of turns () and the cross-sectional area (). Since the new solenoid has 3 times the turns and half the area, the new EMF is , which rounds to .
4.0 V
This answer is incorrect. It implies a much larger increase in EMF than what is mathematically predicted by the changes in coil geometry.
4.5 V
This result would be obtained if the area were doubled instead of halved (). However, the problem states the area is half the original size.
In Victoria, the electrical energy generated at the Loy Yang A power station is transmitted to Melbourne, approximately away, using transmission lines.
Which one of the following best describes the reason for the use of high-voltage transmission of electrical energy over long distances?
Transformers can be used to increase the voltage.
High voltages reduce energy losses in the transmission lines.
High voltages can easily carry the large power required by cities.
High voltages reduce the overall total resistance in the transmission lines.
Reveal Answer
Transformers can be used to increase the voltage.
While transformers are indeed used to step up the voltage, this explains how high voltages are achieved, not why they are beneficial for long-distance transmission.
High voltages reduce energy losses in the transmission lines.
For a given amount of power, transmitting at a higher voltage reduces the current (). A lower current significantly reduces the power lost as heat in the transmission lines ().
High voltages can easily carry the large power required by cities.
While high voltages are used to transmit large amounts of power, the fundamental reason for stepping up the voltage is to minimize power loss during transmission, not just to increase capacity.
High voltages reduce the overall total resistance in the transmission lines.
The resistance of a transmission line is determined by its physical properties (material, length, and cross-sectional area), not by the voltage applied to it.
A solenoid with 24 loops of wire produces an EMF of 36 V during a magnetic flux change of 0.3 Wb.
Calculate the period during which the magnetic flux varied.
0.2 s
0.5 s
2.2 s
5.0 s
Reveal Answer
0.2 s
This is the correct answer. Using Faraday's Law , we can rearrange to solve for time: .
0.5 s
This is incorrect. It does not match the result derived from Faraday's Law using the given values for loops, flux change, and EMF.
2.2 s
This is incorrect. The calculation using the formula yields 0.2 s, not 2.2 s.
5.0 s
This is incorrect. This result likely comes from incorrectly inverting the formula to , which results in .
A laptop computer requires a transformer to reduce the voltage to its rechargeable battery while the battery is charging. The power point supplies an RMS voltage of 240 V and delivers an RMS current of 0.35 A. The transformer converts the voltage to an RMS voltage of 8.0 V. Assume that the transformer is ideal.
Calculate the ratio of the number of turns . Show your working.
Reveal Answer
| Descriptor | Marks |
|---|---|
Correct substitution into the transformer equation, e.g., | 1 |
Correct final answer of or | 1 |
Calculate the RMS current delivered by the power point while the battery is charging.
Reveal Answer
| Descriptor | Marks |
|---|---|
Applies the ideal transformer equation to relate primary and secondary voltages and currents, e.g., or | 1 |
Calculates the correct RMS current delivered to the battery of | 1 |
A magnet moving through a coil of wire will induce a current with a magnetic field
parallel to the electric field.
opposite in direction to the change in flux.
inversely proportional to the electromotive force.
that will continue to fluctuate once the magnet is removed.
Reveal Answer
parallel to the electric field.
The magnetic field lines generated by a current circle around the wire, making them perpendicular, not parallel, to the electric field driving the current.
opposite in direction to the change in flux.
According to Lenz's Law, the induced current creates a magnetic field that opposes the change in magnetic flux that produced it.
inversely proportional to the electromotive force.
The strength of the induced magnetic field is directly proportional to the current, which is directly proportional to the electromotive force (EMF) via Ohm's Law ().
that will continue to fluctuate once the magnet is removed.
Induction requires a changing magnetic flux; once the magnet is removed and the flux stops changing, the induced current and its magnetic field cease.
An ideal step-down transformer has a primary-to-secondary turns ratio of 6:1.
The input power at the primary is , and the input voltage is AC and has an RMS value of .
Which one of the following is closest to the output current of the transformer?
Reveal Answer
This is the primary (input) current, calculated as , rather than the secondary (output) current.
In an ideal transformer, power is conserved (). The secondary voltage is , making the output current .
This value likely comes from confusing the turns ratio () with the actual output current, or incorrectly multiplying the output current by .
This is a miscalculation. The correct output current must be found by dividing the conserved power () by the stepped-down secondary voltage ().
A coil of wire with 100 turns and a radius of 1.4 cm is placed perpendicular to a magnetic field of strength 0.510 T. The magnetic field strength is then changed to 0.030 T in 0.020 s.
Calculate the magnitude of electromotive force (emf) (V) induced in the coil. Show your working.
Reveal Answer
Magnitude of emf =
| Descriptor | Marks |
|---|---|
converts the radius to SI units (from cm to m) | 1 |
determines the area of the coil | 1 |
recognises the scenario relates to induction of an electromotive force by using the equation | 1 |
calculates emf | 1 |
The mains voltage in a particular part of Australia is AC with a voltage of 240 .
Which one of the following is closest to the peak-to-peak voltage, , for this mains voltage?
170 V
340 V
480 V
680 V
Reveal Answer
170 V
Incorrect. This value is approximately , which incorrectly divides the RMS voltage by instead of multiplying it to find the peak voltage.
340 V
Incorrect. This is the peak voltage ( V), but the question asks for the peak-to-peak voltage, which is double this value.
480 V
Incorrect. This value is simply double the RMS voltage ( V), which ignores the factor required to convert RMS to peak voltage.
680 V
Correct. The peak voltage is V. The peak-to-peak voltage is double the peak voltage, V, which is closest to 680 V.
Electromotive force is
the production of voltage across an electrical conductor due to its dynamic interaction with a magnetic field.
a difference in potential that tends to give rise to an electric current.
the repulsion experienced by two negatively charged particles.
one of the four fundamental forces.
Reveal Answer
the production of voltage across an electrical conductor due to its dynamic interaction with a magnetic field.
This describes electromagnetic induction, a specific mechanism that generates EMF, rather than the general definition of electromotive force itself.
a difference in potential that tends to give rise to an electric current.
Electromotive force (EMF) is defined as the energy per unit charge supplied by a source (like a battery or generator), creating the potential difference necessary to drive an electric current.
the repulsion experienced by two negatively charged particles.
This describes the electrostatic force (Coulomb repulsion) between like charges, whereas EMF is a potential difference measured in Volts (), not a force measured in Newtons ().
one of the four fundamental forces.
Despite its name, electromotive force is not a force in the physical sense (measured in Newtons); it is an electric potential. The fundamental force is the electromagnetic force.
Electrical power stations are often situated far from the cities that require the power that they generate.
Which one of the following best describes the reason for the high-voltage transmission of electrical energy?
Transformers can be used to increase the voltage in the cities.
High voltages reduce the energy losses in the transmission lines.
High voltages provide the large currents needed for efficient transmission.
High voltages can reduce the overall total resistance in the transmission lines.
Reveal Answer
Transformers can be used to increase the voltage in the cities.
Transformers are actually used to step down (decrease) the voltage in cities to safe levels for consumer use, not increase it.
High voltages reduce the energy losses in the transmission lines.
For a given amount of power (), transmitting at a high voltage () requires a lower current (). Since power lost as heat in the wires is , reducing the current significantly minimizes energy losses.
High voltages provide the large currents needed for efficient transmission.
High voltages actually result in smaller currents for a given power output. It is the reduction in current, not an increase, that makes transmission efficient.
High voltages can reduce the overall total resistance in the transmission lines.
The resistance of transmission lines is determined by their physical properties (material, length, and cross-sectional area), not by the voltage transmitted through them.
Which of the following is Lenz's Law?
The total electric charge of an isolated system remains constant regardless of changes within the system.
The magnetic flux around a current-carrying wire changes in proportion to the rate of change of the current.
The direction of an induced electric current always opposes the change in the circuit or magnetic field that produces it.
The ratio of the sines of the angles of incidence and refraction of a wave is constant when the wave passes between two given media.
Reveal Answer
The total electric charge of an isolated system remains constant regardless of changes within the system.
This statement defines the Law of Conservation of Charge, which states that the net charge of an isolated system cannot change.
The magnetic flux around a current-carrying wire changes in proportion to the rate of change of the current.
This describes the concept of self-inductance, where a changing current induces a magnetic flux, but it does not define Lenz's Law.
The direction of an induced electric current always opposes the change in the circuit or magnetic field that produces it.
Lenz's Law states that the direction of an induced current is such that it creates a magnetic field opposing the change in magnetic flux that produced it, represented by the negative sign in Faraday's Law.
The ratio of the sines of the angles of incidence and refraction of a wave is constant when the wave passes between two given media.
This statement defines Snell's Law, which relates the angles of incidence and refraction to the refractive indices of two media.