VCAA Chemistry How are organic compounds categorised and synthesised?

15 sample questions with marking guides and sample answers

Q17
2025
SCSA
1 mark
Q17
1 mark

Which of the following is the IUPAC name for an isomer of propyl butanoate?

A

methyl pentanoate

B

heptanoic acid

C

6-methylpentanoic acid

D

3-propylbutanoic acid

Reveal Answer
A

methyl pentanoate

Methyl pentanoate contains 6 carbons (11 from methyl + 55 from pentanoate), whereas propyl butanoate contains 7 carbons (33 from propyl + 44 from butanoate). Isomers must have the same molecular formula.

B

heptanoic acid

Correct Answer

Propyl butanoate is an ester with the formula C7H14O2C_7H_{14}O_2 (3+4=73+4=7 carbons). Heptanoic acid is a carboxylic acid with the same formula C7H14O2C_7H_{14}O_2. Esters and carboxylic acids with the same number of carbon atoms are functional isomers.

C

6-methylpentanoic acid

This name is invalid because a pentanoic acid chain only has 5 carbons, so a substituent cannot be at position 6. Furthermore, a methyl pentanoic acid derivative would only have 6 carbons total, not the required 7.

D

3-propylbutanoic acid

Although a structure constructed from this name would have 7 carbons, '3-propylbutanoic acid' is not a valid IUPAC name. The propyl group would extend the longest carbon chain, making the correct parent name hexanoic acid (specifically 3-methylhexanoic acid).

Q1
2023
QCAA
Paper 2
2 marks
Q1
2 marks

Polylactic acid (PLA) and low-density polyethylene (LDPE) are both used to produce plastic wrapping film.

PlasticCompositionDensity (g/cm3^3)Tensile stress (MPa)Elongation (%)Degradation rate
PLAplant-based1.24606slow
LDPEpetrochemical-based0.9212148none

Analyse the data to discuss one advantage and one disadvantage of using PLA rather than LDPE to produce plastic wrapping film.

Advantage:

Disadvantage:

Reveal Answer

Advantage: An advantage is that PLA is plant based, therefore it uses (renewable) natural resources while LDPE is produced from non-renewable fossil fuels.
Disadvantage: PLA has less % elongation than LDPE, therefore PLA would stretch less.

Marking Criteria
DescriptorMarks

identifies an advantage of using PLA using data

1

identifies a disadvantage of using PLA using data

1
Q18
2024
VCAA
1 mark
Q18
1 mark

Each of the following compounds has a molar mass of 88 g mol188 \text{ g mol}^{-1}.

Which one has the highest boiling point?

A

CH3CH2OCOCH3\text{CH}_3\text{CH}_2\text{OCOCH}_3

B

CH3(CH2)2COOH\text{CH}_3(\text{CH}_2)_2\text{COOH}

C

CH3(CH2)3CH2OH\text{CH}_3(\text{CH}_2)_3\text{CH}_2\text{OH}

D

CH3NH(CH2)2NHCH3\text{CH}_3\text{NH}(\text{CH}_2)_2\text{NHCH}_3

Reveal Answer
A

CH3CH2OCOCH3\text{CH}_3\text{CH}_2\text{OCOCH}_3

Esters cannot form intermolecular hydrogen bonds, resulting in weaker dipole-dipole interactions and a lower boiling point compared to alcohols and carboxylic acids.

B

CH3(CH2)2COOH\text{CH}_3(\text{CH}_2)_2\text{COOH}

Correct Answer

Carboxylic acids can form strong intermolecular hydrogen bonds, often forming stable dimers. This significantly increases their intermolecular forces and gives them the highest boiling point among compounds of similar molar mass.

C

CH3(CH2)3CH2OH\text{CH}_3(\text{CH}_2)_3\text{CH}_2\text{OH}

While alcohols can form hydrogen bonds, they do not form stable dimers like carboxylic acids do, resulting in slightly weaker overall intermolecular forces and a lower boiling point than option B.

D

CH3NH(CH2)2NHCH3\text{CH}_3\text{NH}(\text{CH}_2)_2\text{NHCH}_3

Amines can form hydrogen bonds, but because nitrogen is less electronegative than oxygen, the N-H bond is less polar than the O-H bond. This makes their hydrogen bonds weaker than those in alcohols and carboxylic acids.

Q18
2021
QCAA
Paper 1
1 mark
Q18
1 mark

Identify the major product when 2-methylbut-2-ene reacts with water under acidic conditions.

A

(CH3_3)2_2CHCOCH3_3

B

(CH3_3)2_2C(OH)CH2_2CH3_3

C

(CH3_3)2_2CHCH(OH)CH3_3

D

(CH3_3)2_2C(OH)CH(OH)CH3_3

Reveal Answer
A

(CH3_3)2_2CHCOCH3_3

This is a ketone (3-methyl-2-butanone). Acid-catalyzed hydration of alkenes produces alcohols, not carbonyl compounds; ketones are typically formed from the hydration of alkynes or oxidation of alcohols.

B

(CH3_3)2_2C(OH)CH2_2CH3_3

Correct Answer

The reaction follows Markovnikov's rule, proceeding via the most stable tertiary carbocation intermediate. The hydroxyl group (OH-OH) attaches to the more substituted carbon, yielding the tertiary alcohol 2-methyl-2-butanol.

C

(CH3_3)2_2CHCH(OH)CH3_3

This is the anti-Markovnikov product (3-methyl-2-butanol). The reaction does not favor the formation of the less stable secondary carbocation intermediate required to produce this secondary alcohol.

D

(CH3_3)2_2C(OH)CH(OH)CH3_3

This is a vicinal diol. Acid-catalyzed hydration adds water (HOHH-OH) across the double bond to form a mono-alcohol, whereas diols are formed through oxidation reactions like dihydroxylation.

Q7
2020
VCAA
1 mark
Q7
1 mark

How many structural isomers have the molecular formula C3H6BrCl\text{C}_3\text{H}_6\text{BrCl}?

A

4

B

5

C

6

D

7

Reveal Answer
A

4

This is incorrect because there are more than 4 structural isomers. This answer likely misses one of the positional combinations of the halogens on the propane chain.

B

5

Correct Answer

This is correct. The five structural isomers are 1-bromo-1-chloropropane, 1-bromo-2-chloropropane, 1-bromo-3-chloropropane, 2-bromo-1-chloropropane, and 2-bromo-2-chloropropane.

C

6

This is incorrect because it overcounts the number of structural isomers. There are exactly 5 unique positional combinations for one bromine and one chlorine atom on a propane chain.

D

7

This is incorrect because it overcounts the number of structural isomers. Stereoisomers (enantiomers) are not counted when specifically asking for structural isomers.

Q22
2024
VCAA
1 mark
Q22
1 mark

Use the following information to answer the question.

A triglyceride is reacted with methanol, CH3OH\text{CH}_3\text{OH}, in the presence of concentrated KOH(aq)\text{KOH}(\text{aq}). The products of this reaction are glycerol and Compound J.

The molecular formula of Compound J is C19H30O2\text{C}_{19}\text{H}_{30}\text{O}_2.

What is the molecular formula of the triglyceride?

A

C54H82O3\text{C}_{54}\text{H}_{82}\text{O}_3

B

C54H82O6\text{C}_{54}\text{H}_{82}\text{O}_6

C

C57H84O3\text{C}_{57}\text{H}_{84}\text{O}_3

D

C57H86O6\text{C}_{57}\text{H}_{86}\text{O}_6

Reveal Answer
A

C54H82O3\text{C}_{54}\text{H}_{82}\text{O}_3

This formula is incorrect because a triglyceride must contain 6 oxygen atoms, not 3, and the carbon and hydrogen counts do not balance the transesterification reaction.

B

C54H82O6\text{C}_{54}\text{H}_{82}\text{O}_6

This formula is incorrect because it fails to account for the 3 carbon atoms from the glycerol backbone, resulting in 54 carbons instead of 57.

C

C57H84O3\text{C}_{57}\text{H}_{84}\text{O}_3

This formula is incorrect because a triglyceride contains 3 ester groups, meaning it must have 6 oxygen atoms, not 3.

D

C57H86O6\text{C}_{57}\text{H}_{86}\text{O}_6

Correct Answer

This is correct. In the transesterification reaction, 1 Triglyceride + 3 Methanol (CH4O\text{CH}_4\text{O}) \rightarrow 1 Glycerol (C3H8O3\text{C}_3\text{H}_8\text{O}_3) + 3 Compound J (C19H30O2\text{C}_{19}\text{H}_{30}\text{O}_2). Balancing the atoms yields C57H86O6\text{C}_{57}\text{H}_{86}\text{O}_6.

Q9
2021
QCAA
Paper 1
1 mark
Q9
1 mark

The boiling points of methane, ethane and propane increase as the lengths of the carbon chains increase because more energy is required to overcome the

A

intramolecular hydrogen bonds.

B

intermolecular hydrogen bonds.

C

intramolecular dispersion forces.

D

intermolecular dispersion forces.

Reveal Answer
A

intramolecular hydrogen bonds.

Intramolecular forces hold atoms together within a molecule; boiling involves separating molecules from one another, not breaking bonds within them. Furthermore, alkanes do not contain the electronegative atoms necessary for hydrogen bonding.

B

intermolecular hydrogen bonds.

Alkanes are nonpolar hydrocarbons that lack the hydrogen atoms bonded to highly electronegative atoms (N, O, F) required to form hydrogen bonds.

C

intramolecular dispersion forces.

Dispersion forces are intermolecular (between molecules), not intramolecular. Intramolecular forces refer to the covalent bonds holding the carbon and hydrogen atoms together.

D

intermolecular dispersion forces.

Correct Answer

Boiling requires overcoming intermolecular forces. As the carbon chain length increases, the molecule's surface area and electron count increase, leading to stronger London dispersion forces that require more energy to overcome.

Q12
2021
QCAA
Paper 1
1 mark
Q12
1 mark

Green chemistry principles include the design of chemical synthesis processes that

A

use renewable raw materials and minimise unwanted products.

B

use renewable raw materials and minimise unwanted reactants.

C

use non-renewable raw materials and minimise unwanted products.

D

use non-renewable raw materials and minimise unwanted reactants.

Reveal Answer
A

use renewable raw materials and minimise unwanted products.

Correct Answer

Green chemistry principles explicitly advocate for the use of renewable feedstocks (Principle 7) and the prevention of waste by minimizing the formation of unwanted by-products (Principles 1 and 2).

B

use renewable raw materials and minimise unwanted reactants.

While using renewable materials is a core goal, the principles focus on minimizing waste (unwanted products) generated during the reaction, rather than minimizing reactants.

C

use non-renewable raw materials and minimise unwanted products.

Green chemistry promotes the transition to renewable raw materials (such as agricultural products) rather than relying on depleting non-renewable resources like petroleum.

D

use non-renewable raw materials and minimise unwanted reactants.

This option is incorrect because green chemistry aims to use renewable resources, and the primary objective regarding synthesis efficiency is the reduction of waste products.

Q13
2023
VCAA
1 mark
Q13
1 mark

Which molecule can exist as both a cis and a trans isomer?

A

CH2CBrCl\text{CH}_2\text{CBrCl}

B

CH3CHBrCl\text{CH}_3\text{CHBrCl}

C

CH3CHCHCl\text{CH}_3\text{CHCHCl}

D

(CH3)2CCCl2(\text{CH}_3)_2\text{CCCl}_2

Reveal Answer
A

CH2CBrCl\text{CH}_2\text{CBrCl}

The molecule CH2=CBrCl\text{CH}_2=\text{CBrCl} has two identical hydrogen atoms on one of the double-bonded carbons, which prevents cis-trans isomerism.

B

CH3CHBrCl\text{CH}_3\text{CHBrCl}

The molecule CH3CHBrCl\text{CH}_3\text{CHBrCl} is an alkane with only single bonds, so it cannot exhibit cis-trans isomerism (though it does have enantiomers).

C

CH3CHCHCl\text{CH}_3\text{CHCHCl}

Correct Answer

The molecule CH3CH=CHCl\text{CH}_3\text{CH}=\text{CHCl} has a carbon-carbon double bond where each carbon is attached to two different groups, satisfying the requirements for cis and trans isomers.

D

(CH3)2CCCl2(\text{CH}_3)_2\text{CCCl}_2

The molecule (CH3)2C=CCl2(\text{CH}_3)_2\text{C}=\text{CCl}_2 has identical groups on both carbons of the double bond (two methyls on one, two chlorines on the other), making cis-trans isomerism impossible.

Q23
2022
QCAA
Paper 1
4 marks
Q23
4 marks

Ibuprofen is manufactured using two different processes.

ProcessNumber of reagents usedReagentsReagentsIbuprofenIbuprofenWaste productsWaste products
  AtomsMr\text{M}_\text{r}AtomsMr\text{M}_\text{r}AtomsMr\text{M}_\text{r}
17C20H42NO10ClNa\text{C}_{20}\text{H}_{42}\text{NO}_{10}\text{ClNa}514.5C13H18O2\text{C}_{13}\text{H}_{18}\text{O}_2206.0C7H24NO8ClNa\text{C}_7\text{H}_{24}\text{NO}_8\text{ClNa}308.5
24C15H22O4\text{C}_{15}\text{H}_{22}\text{O}_4266.0C13H18O2\text{C}_{13}\text{H}_{18}\text{O}_2206.0C2H4O2\text{C}_2\text{H}_4\text{O}_260.0

Calculate the atom economy for each process and draw conclusions about the economic and environmental impact of each process.

Reveal Answer

Process 1: atom economy = 206.0/514.5×100=40.04%206.0/514.5 \times 100 = 40.04\%
Process 2: atom economy = 206.0/266.0×100=77.44%206.0/266.0 \times 100 = 77.44\%
Process 2 has 37.4% better atom economy than process 1

Economic impact: Process 2 has a better atom economy than process 1 (fewer reagents are required).
Environmental impact: Process 2 is greener than process 1 because fewer waste products (atoms) are produced.

Marking Criteria
DescriptorMarks

Calculates atom economy for Process 1 as 40%

1

Calculates atom economy for Process 2 as 77%

1

Concludes process 2 is cheaper as fewer reagent atoms are required

1

Concludes process 2 is greener as fewer waste atoms are produced

1
Q9
2024
QCAA
Paper 1
1 mark
Q9
1 mark

Polytetrafluorethene (PTFE) has a higher melting point than polypropene (PP) due to the

A

C–F bonds being non-reactive.

B

fluorine atoms forming stable C–F covalent bonds.

C

dispersion forces between closely packed fluorocarbon chains.

D

dipole–dipole interaction between fluorine and carbon atoms within the fluorocarbon chain.

Reveal Answer
A

C–F bonds being non-reactive.

Chemical reactivity refers to the stability of the molecule against chemical changes, whereas the melting point is a physical property determined by the strength of intermolecular forces.

B

fluorine atoms forming stable C–F covalent bonds.

The strength of covalent bonds determines the polymer's thermal stability (resistance to decomposition), but the melting point is governed by the intermolecular forces holding separate chains together.

C

dispersion forces between closely packed fluorocarbon chains.

Correct Answer

PTFE chains are linear and rigid, allowing them to pack very closely. This dense packing results in strong cumulative London dispersion forces between the chains, requiring significant energy to overcome.

D

dipole–dipole interaction between fluorine and carbon atoms within the fluorocarbon chain.

Melting involves overcoming forces between different polymer chains (intermolecular), whereas interactions between atoms within the same chain (intramolecular) determine the chain's structure and stiffness.

Q22
2023
QCAA
Paper 1
4 marks
Q22a
2 marks

Write a balanced chemical equation to describe how polytetrafluorethene (PTFE) is produced from its monomer.

Reveal Answer

nF2C=CF2[F2CCF2]nnF_2C=CF_2 \rightarrow \left[ F_2C-CF_2 \right]_n

Marking Criteria
DescriptorMarks

describes formulas for tetrafluorethene monomer and polytetrafluorethene polymer

1

provides a balanced equation

1
Q22b
2 marks

Determine whether polytetrafluorethene is an addition or condensation polymer. Explain your reasoning.

Reveal Answer

Addition polymer
The double bond in tetrafluorethene is broken to allow the monomers to join.

Marking Criteria
DescriptorMarks

identifies addition polymer

1

explains double bond in monomer is broken to allow the formation of polymer

1
Q14
2023
QCAA
Paper 1
1 mark
Q14
1 mark

Identify which molecule has the lowest boiling point.

A

butanone

B

hexanone

C

pentanone

D

propanone

Reveal Answer
A

butanone

Butanone (C4H8OC_4H_8O) has a longer carbon chain than propanone, leading to stronger London dispersion forces and a higher boiling point.

B

hexanone

Hexanone (C6H12OC_6H_{12}O) has the highest molecular weight and longest carbon chain among the options, resulting in the strongest intermolecular forces and the highest boiling point.

C

pentanone

Pentanone (C5H10OC_5H_{10}O) has a larger molecular size than propanone, which results in stronger intermolecular attractions and a higher boiling point.

D

propanone

Correct Answer

Propanone (C3H6OC_3H_6O) has the shortest carbon chain and lowest molecular mass, resulting in the weakest London dispersion forces and therefore the lowest boiling point.

Q13
2023
QCAA
Paper 1
1 mark
Q13
1 mark

Identify the reaction used to produce methanol and triglycerides.

A

oxidation

B

substitution

C

saponification

D

transesterification

Reveal Answer
A

oxidation

Oxidation involves the loss of electrons or the addition of oxygen to a molecule. It is not the reaction mechanism used for exchanging ester groups between triglycerides and alcohols.

B

substitution

While the underlying mechanism is a nucleophilic acyl substitution, this is a broad category. The specific term for the reaction between an ester and an alcohol is transesterification.

C

saponification

Saponification is the base-catalyzed hydrolysis of triglycerides to produce glycerol and fatty acid salts (soap), rather than the reaction involving methanol to exchange ester groups.

D

transesterification

Correct Answer

Transesterification is the reaction where the organic group of an ester is exchanged with the organic group of an alcohol. It is the specific process governing the interconversion between triglycerides plus methanol and methyl esters plus glycerol.

Q2
2022
QCAA
Paper 1
1 mark
Q2
1 mark

Structural isomers are compounds with the same molecular formula but a different

A

molar mass.

B

molecular mass.

C

empirical formula.

D

arrangement of atoms.

Reveal Answer
A

molar mass.

Since structural isomers share the same molecular formula, they contain the exact same number of atoms of each element and therefore have identical molar masses.

B

molecular mass.

Molecular mass is determined by the sum of the atomic masses in the molecular formula; since isomers have the same formula, their molecular masses are the same.

C

empirical formula.

The empirical formula represents the simplest ratio of elements; because the molecular formula is identical for isomers, their empirical formulas are also identical.

D

arrangement of atoms.

Correct Answer

Structural isomers are defined as compounds that have the same molecular formula but differ in the connectivity or bonding arrangement of their atoms.

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