VCAA Chemistry How are organic compounds analysed and used?
15 sample questions with marking guides and sample answers
Use the following information to answer the question.
A solution of citric acid, , was analysed by titration.
25.0 mL aliquots of the solution were titrated against a standardised solution of 0.0250 M sodium hydroxide, NaOH. Phenolphthalein indicator was used and the average titre was found to be 24.0 mL.
Based on the titration, the concentration of in the solution was
Reveal Answer
Citric acid is triprotic, reacting with NaOH in a 1:3 ratio. The moles of NaOH used is mol, so the moles of acid is mol. Dividing by the aliquot volume (0.0250 L) gives M.
This incorrect answer is obtained by mistakenly swapping the volumes of the acid and base in the concentration calculation.
This error occurs if the volumes of the acid and base are swapped and the 1:3 stoichiometric ratio between citric acid and NaOH is ignored.
This incorrect result comes from multiplying the moles of NaOH by 3 instead of dividing by 3 to find the moles of the triprotic citric acid.
The NMR spectrum of an organic compound has three unique sets of peaks: a single peak, seven peaks (septet) and two peaks (doublet).
The compound is
3-methyl butanoic acid.
2-methyl propanoic acid.
2-chloro-2-methylpropane.
1,2-dichloro-2-methylpropane.
Reveal Answer
3-methyl butanoic acid.
3-methylbutanoic acid has four unique sets of protons, which would produce a singlet (OH), a doublet (CH3 groups), a multiplet/nonet (CH), and another doublet (CH2).
2-methyl propanoic acid.
2-methylpropanoic acid has three unique sets of protons: the carboxylic acid proton (singlet), the CH proton split by six methyl protons (septet), and the six equivalent methyl protons split by the CH proton (doublet).
2-chloro-2-methylpropane.
2-chloro-2-methylpropane has only one unique set of protons (nine equivalent methyl protons), which would produce a single peak (singlet) in its NMR spectrum.
1,2-dichloro-2-methylpropane.
1,2-dichloro-2-methylpropane has two unique sets of protons that are not adjacent to any other protons, which would result in a spectrum with two singlets.
Enzymes are commonly not effective in acidic conditions because acids
change the charges on the enzymes.
react with the enzymes to form zwitterions.
esterify the enzymes into smaller molecules.
react with the carboxyl groups on the enzymes' amino acid residues.
Reveal Answer
change the charges on the enzymes.
Acidic conditions increase the concentration of ions, which protonate amino acid side chains. This alters the enzyme's overall charge distribution, disrupting the ionic bonds that maintain its functional 3D structure.
react with the enzymes to form zwitterions.
Zwitterions are molecules with both positive and negative charges that net to zero, typically occurring at an amino acid's isoelectric point. In highly acidic conditions, amino acids become positively charged cations, not zwitterions.
esterify the enzymes into smaller molecules.
Acids do not esterify enzymes into smaller molecules. Breaking down an enzyme's protein chain into smaller molecules would involve the hydrolysis of peptide bonds, not esterification.
react with the carboxyl groups on the enzymes' amino acid residues.
While acidic conditions do protonate carboxylate groups into neutral carboxyl groups, this is only a partial explanation. The loss of enzyme effectiveness is due to the overall change in charges across all ionizable groups, which disrupts the active site.
Which of the following will decolourise a solution of bromine water?
1.0 mol L solution
1.0 mol L KCl solution
Reveal Answer
1.0 mol L solution
This is a solution of Iron(III) nitrate. Neither nor ions react with bromine water, so the solution would not be decolourised.
1.0 mol L KCl solution
Chloride ions () cannot reduce bromine () because chlorine is a stronger oxidising agent than bromine. Therefore, no reaction occurs to remove the bromine colour.
Pentanal (C₅H₁₀O) can cause a colour change with bromine because it is an aldehyde. Aldehydes are easily oxidised to carboxylic acids, and in this reaction, bromine (Br₂), which is orange-brown, is reduced to colourless bromide ions (Br⁻). As a result, the orange colour of bromine water disappears when it reacts with pentanal.
The condensed formula represents 2-pentene, which contains a carbon-carbon double bond (). Alkenes undergo a rapid addition reaction with bromine water, consuming the and turning the orange solution colourless.
During fermentation, yeast will produce other volatile polar compounds that have similar boiling points to ethanol, .
Which one of the following methods would be most suitable to separate these compounds from ?
solvent extraction
simple distillation
fractional distillation
solvent extraction and distillation
Reveal Answer
solvent extraction
Solvent extraction relies on differences in solubility, which would likely be ineffective here since both ethanol and the other compounds are polar and may dissolve in similar solvents.
simple distillation
Simple distillation is only effective for separating liquids with significantly different boiling points (typically a difference of at least 25°C).
fractional distillation
Fractional distillation is specifically designed to separate miscible volatile liquids that have very similar boiling points.
solvent extraction and distillation
Adding solvent extraction is unnecessary and less efficient, as fractional distillation alone is the standard and most effective method for separating liquids with similar boiling points.
Enzymes are classified as
carbohydrates.
proteins.
starches.
lipids.
Reveal Answer
carbohydrates.
Carbohydrates are organic compounds like sugars and fibers used primarily for energy and structure, not for catalyzing reactions.
proteins.
Enzymes are biological catalysts composed of amino acid chains folded into specific shapes, classifying them as proteins.
starches.
Starches are complex carbohydrates (polysaccharides) used for energy storage in plants, whereas enzymes are the proteins that might break them down.
lipids.
Lipids include fats, oils, and waxes used for long-term energy storage and membrane structure, but they do not function as biological catalysts.
Use the following information to answer the question.
A solution of citric acid, , was analysed by titration.
25.0 mL aliquots of the solution were titrated against a standardised solution of 0.0250 M sodium hydroxide, NaOH. Phenolphthalein indicator was used and the average titre was found to be 24.0 mL.
Which one of the following would have resulted in a concentration that is higher than the actual concentration?
The pipette was rinsed with NaOH solution.
The pipette was rinsed with solution.
The conical flask was rinsed with NaOH solution.
The conical flask was rinsed with solution.
Reveal Answer
The pipette was rinsed with NaOH solution.
Rinsing the pipette with NaOH would neutralize some of the citric acid before it is transferred to the flask. This decreases the required NaOH titre, resulting in a lower calculated concentration.
The pipette was rinsed with solution.
Rinsing the pipette with the solution it will transfer (citric acid) is the standard correct procedure and ensures the concentration remains accurate.
The conical flask was rinsed with NaOH solution.
Rinsing the conical flask with NaOH adds extra base to the flask, which neutralizes some of the citric acid before titration begins. This decreases the required NaOH titre, leading to a lower calculated concentration.
The conical flask was rinsed with solution.
Rinsing the conical flask with citric acid leaves residual acid in the flask, meaning there is more acid present than just the 25.0 mL aliquot. This requires a larger volume of NaOH to neutralize, leading to a higher calculated concentration.
Which one of the following statements about IR spectroscopy is correct?
IR radiation changes the spin state of electrons.
Bond wave number is influenced only by bond strength.
An IR spectrum can be used to determine the purity of a sample.
In an IR spectrum, high transmittance corresponds to high absorption.
Reveal Answer
IR radiation changes the spin state of electrons.
IR radiation causes changes in the vibrational states of molecules, not the spin states of electrons (which is associated with Electron Paramagnetic Resonance spectroscopy).
Bond wave number is influenced only by bond strength.
The wavenumber of a bond's vibration depends on both the bond strength (force constant) and the reduced mass of the atoms involved, as described by Hooke's Law.
An IR spectrum can be used to determine the purity of a sample.
An IR spectrum can reveal the presence of impurities if unexpected absorption peaks appear that do not belong to the pure compound.
In an IR spectrum, high transmittance corresponds to high absorption.
Transmittance and absorbance are inversely related; high transmittance means that most of the light passed through the sample, indicating low absorption.
Dispersion forces, hydrogen bonding, disulfide bridges and ionic bonding all contribute to the
primary structure of proteins.
secondary structure of proteins.
tertiary structure of proteins.
quaternary structure of proteins.
Reveal Answer
primary structure of proteins.
Primary structure refers to the linear sequence of amino acids held together specifically by covalent peptide bonds, not by the various side-chain interactions listed.
secondary structure of proteins.
Secondary structure, such as -helices and -sheets, is primarily stabilized by hydrogen bonds between the backbone amide and carbonyl groups, rather than interactions between side chains.
tertiary structure of proteins.
Tertiary structure is the overall three-dimensional shape of a polypeptide, stabilized by interactions between R groups (side chains) including dispersion forces, hydrogen bonds, ionic bonds (salt bridges), and covalent disulfide bridges.
quaternary structure of proteins.
Quaternary structure refers specifically to the arrangement of multiple polypeptide subunits; while these forces hold subunits together, the question describes the forces defining the 3D fold of a single chain (tertiary structure).
The equivalence point of an acid–base titration occurs when the
pH equals the p.
pH stops changing.
indicator changes colour.
titrant completely neutralises the analyte.
Reveal Answer
pH equals the p.
The pH equals the p at the half-equivalence point, where exactly half of the weak acid has been converted to its conjugate base.
pH stops changing.
The pH changes most rapidly at the equivalence point rather than stopping; it only levels off significantly after excess titrant is added.
indicator changes colour.
The point where the indicator changes colour is called the end point, which is an experimental approximation that should ideally be close to the equivalence point.
titrant completely neutralises the analyte.
The equivalence point is defined as the stoichiometric point where the moles of added titrant exactly equal the moles required to completely react with (neutralise) the analyte.
Use the following information to answer the question.
A chemist runs a mixture of hexane, hexan-1-ol and hexan-2-one through a high-performance liquid chromatography (HPLC) column using a polar mobile phase and a non-polar stationary phase.
The chemist wants to determine the concentration of hexane in the mixture.
Which one of the following will provide information to allow the hexane concentration to be accurately calculated?
running a series of known concentrations of hexane through the HPLC column under the same conditions
running the HPLC experiment using a non-polar mobile phase and a polar stationary phase
using published retention times and peak sizes of standard hexane chromatographs
reducing the HPLC column temperature to achieve better separation of the compounds
Reveal Answer
running a series of known concentrations of hexane through the HPLC column under the same conditions
To accurately determine concentration, a calibration curve must be constructed by running standard solutions of known concentrations under the exact same experimental conditions to compare peak areas.
running the HPLC experiment using a non-polar mobile phase and a polar stationary phase
Changing the polarity of the mobile and stationary phases alters the separation method (switching to normal phase chromatography) but does not provide the quantitative reference data needed to calculate concentration.
using published retention times and peak sizes of standard hexane chromatographs
Retention times and peak sizes are highly dependent on the specific instrument, column age, and exact experimental conditions, so published data cannot be reliably used for quantitative analysis.
reducing the HPLC column temperature to achieve better separation of the compounds
While reducing the temperature might improve the separation (resolution) of the peaks, it does not provide the reference standards required to calculate the actual concentration of the compound.
Which one of the following statements about denaturation is correct?
Denaturation
can only be caused by changes in temperature or the addition of acids.
causes the reversible change of a protein's shape.
hydrolyses the primary structure of a protein.
alters the secondary structure of a protein.
Reveal Answer
can only be caused by changes in temperature or the addition of acids.
Incorrect. Denaturation can be caused by many other factors besides temperature and acids, such as bases, heavy metals, organic solvents, and mechanical agitation.
causes the reversible change of a protein's shape.
Incorrect. Denaturation is most commonly an irreversible process, such as cooking an egg, rather than a reliably reversible change.
hydrolyses the primary structure of a protein.
Incorrect. Denaturation does not break the covalent peptide bonds of the primary structure; a different process called hydrolysis is required to break down a protein's primary sequence.
alters the secondary structure of a protein.
Correct. Denaturation disrupts the non-covalent interactions, such as hydrogen bonds, that maintain a protein's secondary, tertiary, and quaternary structures.
Evelyn titrates 10.0 mL of 0.100 M potassium permanganate, , with 0.100 M oxalic acid, .
The half-equation for the oxidation of oxalic acid in acidic conditions is
What volume of should be added to reach the equivalence point?
4.0 mL
10.0 mL
12.0 mL
25.0 mL
Reveal Answer
4.0 mL
This incorrect volume results from using a 2:5 molar ratio of oxalic acid to permanganate, which is the inverse of the actual stoichiometric ratio.
10.0 mL
This assumes a 1:1 stoichiometric ratio between oxalic acid and potassium permanganate, ignoring the number of electrons transferred in the redox reaction.
12.0 mL
This is a miscalculation. The correct volume must be determined by balancing the electrons transferred in the oxidation and reduction half-reactions.
25.0 mL
The reduction of requires 5 electrons, while the oxidation of oxalic acid produces 2 electrons, resulting in a 5:2 molar ratio of oxalic acid to permanganate. Since the concentrations are equal, of oxalic acid is needed.
Use the following information to answer the question.
A chemist runs a mixture of hexane, hexan-1-ol and hexan-2-one through a high-performance liquid chromatography (HPLC) column using a polar mobile phase and a non-polar stationary phase.
Which of the following shows the chemicals in order of their retention times, from lowest to highest?
hexane, hexan-2-one, hexan-1-ol
hexane, hexan-1-ol, hexan-2-one
hexan-2-one, hexan-1-ol, hexane
hexan-1-ol, hexan-2-one, hexane
Reveal Answer
hexane, hexan-2-one, hexan-1-ol
This order represents the highest to lowest retention time, which would be the correct order if the stationary phase were polar (normal-phase HPLC).
hexane, hexan-1-ol, hexan-2-one
Hexane is the most non-polar compound, meaning it will interact most strongly with the non-polar stationary phase and have the highest, not lowest, retention time.
hexan-2-one, hexan-1-ol, hexane
While hexane correctly has the highest retention time, hexan-1-ol is more polar than hexan-2-one due to its ability to form hydrogen bonds, so hexan-1-ol will elute before hexan-2-one.
hexan-1-ol, hexan-2-one, hexane
In reverse-phase HPLC (non-polar stationary phase, polar mobile phase), the most polar compound has the lowest retention time. Hexan-1-ol (most polar) elutes first, followed by hexan-2-one, and the non-polar hexane elutes last.
Intra-chain hydrogen bonding between peptide groups occurs in
primary protein structures.
secondary protein structures.
tertiary protein structures.
quaternary protein structures.
Reveal Answer
primary protein structures.
Primary structure refers to the linear sequence of amino acids connected by covalent peptide bonds, not hydrogen bonds.
secondary protein structures.
Secondary structures, such as the -helix, are stabilized by intra-chain hydrogen bonds formed between the carbonyl () and amide () groups of the peptide backbone.
tertiary protein structures.
Tertiary structure is the overall 3D shape determined primarily by interactions between amino acid side chains (R-groups), such as disulfide bridges, hydrophobic interactions, and ionic bonds.
quaternary protein structures.
Quaternary structure involves the arrangement of multiple polypeptide subunits held together by inter-chain interactions, rather than intra-chain bonding within a single backbone.