SCSA Physics Science Inquiry Skills

5 sample questions with marking guides and sample answers · Avg. score: 58.4%

Q19
2020
VCAA
1 mark
Q19
1 mark

Which one of the following best describes a hypothesis?

A

a testable scientific explanation

B

a well-tested scientific explanation

C

a scientific explanation by a famous scientist

D

a widely believed and highly plausible explanation

Reveal Answer
A

a testable scientific explanation

Correct Answer

A hypothesis is fundamentally a proposed explanation for a phenomenon that can be tested through experimentation or observation. Testability is the core requirement of any scientific hypothesis.

B

a well-tested scientific explanation

A well-tested and broadly accepted scientific explanation is known as a scientific theory, not a hypothesis. A hypothesis is an initial proposal made before extensive testing occurs.

C

a scientific explanation by a famous scientist

The scientific method relies on empirical evidence and testability, not the authority or fame of the person making the claim.

D

a widely believed and highly plausible explanation

Popular belief or plausibility does not define a hypothesis. A hypothesis must be specifically testable through scientific methods, regardless of how many people currently believe it.

Q20
2024
VCAA
1 mark
Q20
1 mark

Data can be described as precise when

A

it is the result of a careful investigation.

B

the experiment is repeated many times, and the results show little variation.

C

the same experimental methodology is used by different investigators.

D

it is close to the scientifically accepted value of the quantity being measured.

Reveal Answer
A

it is the result of a careful investigation.

While a careful investigation is important in science, it does not define precision, which specifically refers to the consistency of repeated measurements.

B

the experiment is repeated many times, and the results show little variation.

Correct Answer

Precision refers to how close multiple measurements are to each other, meaning repeated trials will show very little variation.

C

the same experimental methodology is used by different investigators.

Having different investigators use the same methodology ensures standardization, but it does not guarantee that the resulting data will have low variance or high precision.

D

it is close to the scientifically accepted value of the quantity being measured.

Being close to the scientifically accepted or true value is the definition of accuracy, not precision.

Q20
2022
VCAA
1 mark
Q20
1 mark

The experimental uncertainty of a measurement is best understood as

A

an estimate of the validity of the data.

B

a mistake in the experimental method used.

C

a mistake in the recording of a measurement.

D

an estimate of the maximum likely difference between the measurement and the true value.

Reveal Answer
A

an estimate of the validity of the data.

Validity refers to how well an experiment measures what it intends to measure, whereas uncertainty quantifies the precision and potential error margin of a specific measurement.

B

a mistake in the experimental method used.

Experimental uncertainty is an inherent part of any measurement process due to equipment limitations, not a procedural mistake or blunder.

C

a mistake in the recording of a measurement.

A mistake in recording data is a human error, whereas uncertainty represents the natural limits of precision in the measuring instrument or process.

D

an estimate of the maximum likely difference between the measurement and the true value.

Correct Answer

Experimental uncertainty provides a quantitative estimate of the range within which the true value of the measurement is expected to lie, accounting for inherent measurement limitations.

Q11
2020
VCAA
4 marks
Q11

An astronaut has left Earth and is travelling on a spaceship at 0.800c (γ = 1.67) directly towards the star known as Sirius, which is located 8.61 light-years away from Earth, as measured by observers on Earth.

Q11a
2 marks

How long will the trip take according to a clock that the astronaut is carrying on his spaceship? Show your working.

Reveal Answer

The distance of 8.61 light-years is the proper length in Earth's frame of reference. The proper time in the Earth's frame of reference is:
t=dv=8.610.8t = \frac{d}{v} = \frac{8.61}{0.8}
t=10.76 yrt = 10.76 \text{ yr}
This time is the dilated time in the astronaut's frame of reference. The proper time as measured by the astronaut is:
t=t0γt = t_0 \gamma
10.76=t0×1.6710.76 = t_0 \times 1.67
t0=6.44 yearst_0 = 6.44 \text{ years}

Marking Criteria
DescriptorMarks

Calculates the time in Earth's frame of reference (10.76 yr10.76 \text{ yr}) OR calculates the contracted length in the astronaut's frame of reference (5.16 ly5.16 \text{ ly})

1

Calculates the correct proper time of 6.44 years6.44 \text{ years}

1
Q11b
2 marks

Is the trip time measured by the astronaut in part a. a proper time? Explain your reasoning.

Reveal Answer

The time measured by the astronaut will be proper time because the clock is stationary in the astronaut's frame of reference.

Marking Criteria
DescriptorMarks

Identifies that the time measured by the astronaut is proper time

1

Explains that this is because the clock is stationary in the astronaut's frame of reference

1
Q20
2025
VCAA
1 mark
Q20
1 mark

Harriet and Tom were investigating how the speed, vv, of a falling object varied with the distance, ss, it had fallen.

They dropped a small steel ball, initially at rest, from the third floor of their school building. The speed of the ball was measured at six positions as it fell.

Air resistance can be ignored.

Which one of the following graphs of their data would be expected to result in a straight line through the origin?

A

vv versus ss

B

vv versus s\sqrt{s}

C

v2v^2 versus s\sqrt{s}

D

v\sqrt{v} versus ss

Reveal Answer
A

vv versus ss

The kinematic equation for an object falling from rest is v2=2gsv^2 = 2gs, meaning vv is proportional to s\sqrt{s}. A graph of vv versus ss would result in a curve, not a straight line.

B

vv versus s\sqrt{s}

Correct Answer

Using the kinematic equation v2=u2+2asv^2 = u^2 + 2as with an initial velocity of u=0u=0, we get v=2gsv = \sqrt{2g}\sqrt{s}. This shows that vv is directly proportional to s\sqrt{s}, which produces a straight line through the origin.

C

v2v^2 versus s\sqrt{s}

Based on the equation v2=2gsv^2 = 2gs, v2v^2 is directly proportional to ss, not s\sqrt{s}. Plotting v2v^2 versus s\sqrt{s} would result in a quadratic curve.

D

v\sqrt{v} versus ss

Since vv is proportional to s1/2s^{1/2}, v\sqrt{v} would be proportional to s1/4s^{1/4}. Plotting v\sqrt{v} versus ss would not produce a straight line.

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