SCSA Chemistry Chemical equilibrium systems
15 sample questions with marking guides and sample answers
Which of the following is likely to occur due to the increase of carbon dioxide levels in the atmosphere?
oceans cool and absorb less carbon dioxide from the atmosphere
it will be more difficult for crustations to construct their shells
the pH of oceans will increase, becoming more acidic
the availability of carbonate ions to marine organisms will increase
Reveal Answer
oceans cool and absorb less carbon dioxide from the atmosphere
Increased atmospheric carbon dioxide contributes to the greenhouse effect and global warming, which causes ocean temperatures to rise, not cool.
it will be more difficult for crustations to construct their shells
Higher carbon dioxide levels lead to ocean acidification, which reduces the availability of carbonate ions that crustaceans and other marine organisms need to build their calcium carbonate shells.
the pH of oceans will increase, becoming more acidic
While the oceans will become more acidic due to increased carbon dioxide absorption, an increase in acidity corresponds to a decrease in pH, not an increase.
the availability of carbonate ions to marine organisms will increase
Ocean acidification increases the concentration of hydrogen ions, which react with carbonate ions to form bicarbonate, thereby decreasing the availability of carbonate ions for marine organisms.
Sulfuric acid is manufactured by the Contact process, the steps of which are outlined below.
Step One: Molten sulfur is burned in air at approximately 1000 °C:
Step Two: The resulting sulfur dioxide is converted to sulfur trioxide as shown in the following equilibrium reaction. It is conducted at a temperature of about 450 °C with a catalyst at a pressure of between 100 and 200 kPa:
Step Three: The resulting sulfur trioxide is absorbed into sulfuric acid, producing oleum (). Water is added to the oleum, producing 18 mol L sulfuric acid:
Use your understanding of collision theory and chemical equilibrium to discuss the reaction conditions for Steps 1 and 2 of the Contact process, given that the aim is to produce the greatest yield in the shortest time. In your discussion, also address economic concerns where appropriate.
Reveal Answer
High temperature increases the average kinetic energy of the particles, which means that the particles collide more frequently. Also, more of these collisions will have energy higher than the activation energy, which means a greater proportion of collisions are successful, and the reaction rate increases. The vanadium catalyst increases the rate of the forward reaction, and also the rate of the reverse reaction to an equal extent, as it provides an alternative pathway with a lower activation energy. Therefore, a greater proportion of the particles will have sufficient energy to react when they collide. High pressure or concentration has more particles per unit volume and so there is a higher frequency of collisions, and the reaction rate increases. As Step 1 is a combustion reaction, it essentially goes to completion at the high temperature and does not require a catalyst or high pressure. For Step 2, high temperature, high pressure and a catalyst would favour a high rate.
For equilibrium, which is only considered for Step 2, high temperature favours the reverse reaction because it is endothermic, and this decreases the SO(g) yield, which is not desired. A low temperature decreases the rate of reaction, which is also not desired. A high pressure favours the forward reaction because there are a greater number of moles of gas reactants, increasing the SO(g) yield which is desired.
Economically, high pressures are costly and dangerous.
Therefore, for Step 2, a compromise is required between the high temperature for rate and the low temperature for yield. A compromise is also required between the cost of higher pressures and the pressure that allows a satisfactory yield and rate.
Rates
| Descriptor | Marks |
|---|---|
1 mark each for any of the following, up to a maximum of 6 marks: Explains that high temperature increases the average kinetic energy of the particles, which means that the particles collide more frequently; Explains that more of these collisions will have energy higher than the activation energy, which means a greater proportion of collisions are successful, and the reaction rate increases; Describes that the vanadium catalyst increases the rate of the forward reaction (and also the rate of the reverse reaction to an equal extent) as it provides an alternative pathway with a lower activation energy; States that a greater proportion of the particles will have sufficient energy to react when they collide; Explains that high pressure (concentration) has more particles per unit volume and so there is a higher frequency of collisions, and the reaction rate increases; Identifies that as Step 1 is a combustion reaction, it essentially goes to completion at the high temperature (and does not require a catalyst or high pressure); States that for Step 2, high temperature, high pressure and catalyst would favour high rate. | 6 |
Equilibrium
| Descriptor | Marks |
|---|---|
1 mark each for any of the following (only considered for Step 2), up to a maximum of 3 marks: Explains that high temperature favours the reverse reaction because it is endothermic, and this decreases the SO3(g) yield; States that a low temperature decreases the rate of reaction; Explains that a high pressure favours the forward reaction because there are a greater number of moles of gas reactants, increasing the SO3(g) yield. | 3 |
Economics
| Descriptor | Marks |
|---|---|
States that high pressures are costly (and dangerous). | 1 |
Compromise
| Descriptor | Marks |
|---|---|
1 mark each for any of the following, up to a maximum of 2 marks: Identifies that for Step 2, a compromise is required between the high temperature for rate and the low temperature for yield; Identifies that a compromise is also required between the cost of higher pressures and the pressure that allows a satisfactory yield and rate. | 2 |
Which of the following processes does not contribute to the building of weaker seashells through ocean acidification?
Reveal Answer
This equilibrium determines the concentration of carbonate ions (). Increased ocean acidity shifts this reaction to the left, reducing the carbonate available for marine organisms to build strong shells.
This reaction represents the dissolution of already-formed calcium carbonate () shells by increased acidity. While it destroys existing shells, it is not a process that inhibits the initial building of new shells.
This reaction shows carbon dioxide dissolving in water to form carbonic acid, which is the primary driver of ocean acidification that ultimately impairs shell building.
This reaction shows the dissociation of carbonic acid into bicarbonate and hydronium ions, which increases ocean acidity and leads to a reduction in the carbonate ions needed for shell building.
The question refers to the decomposition of hydrogen iodide gas (HI) to produce hydrogen gas () and iodine gas () in a sealed 1-litre container.
Colourless Colourless Purple
Determine the equilibrium expression () for the reaction.
Reveal Answer
This is incorrect because the stoichiometric coefficient of the reactant (2) must be used as an exponent, not a multiplier. The correct term is , not .
This is correct based on the law of mass action for the reaction . The concentration of products is in the numerator, the reactant is in the denominator, and the coefficient 2 for HI becomes an exponent.
This is incorrect because it uses atomic species (H, I) instead of the molecular species (, ) actually present in the reaction, and it treats coefficients as multipliers rather than exponents.
This is incorrect because it substitutes atomic concentrations for molecular products and uses coefficients as multipliers in the numerator.
Consider the following statements about fossil fuels and biofuels.
I. Production of biofuels does not damage the environment.
II. Combustion of both biofuels and fossil fuels generates greenhouse gases.
III. Biofuels and fossil fuels are both renewable as they are produced from plants.
Which of the statements above are correct?
I only
II only
I and II only
I and III only
Reveal Answer
I only
This option is incorrect because Statement I is false. The production of biofuels can damage the environment through deforestation, habitat destruction, and the use of agricultural fertilizers.
II only
This is the correct option because only Statement II is true. The combustion of both biofuels and fossil fuels releases carbon dioxide (), which is a greenhouse gas.
I and II only
This option is incorrect because Statement I is false. While Statement II is true, biofuel production is not entirely harmless to the environment.
I and III only
This option is incorrect because both Statements I and III are false. Fossil fuels are considered non-renewable because they take millions of years to form, unlike biofuels which can be replenished relatively quickly.
Consider the following two reactions that are at equilibrium at 500 °C.
The magnitude of the value of for the second reaction is
Reveal Answer
This value is , which would be the equilibrium constant if the first reaction were multiplied by 2 but not reversed.
This value is . When a reaction is multiplied by a coefficient, the equilibrium constant must be raised to that power, not multiplied by it.
This value results from incorrect mathematical manipulation of the equilibrium constant. The correct operation is to take the inverse square of the original .
The second reaction is the reverse of the first reaction multiplied by 2. Therefore, its equilibrium constant is .
Consider the following statements about coal seam gas and petroleum gas.
I. Coal seam gas and petroleum gas are both mixtures.
II. Coal seam gas and petroleum gas both combust to produce carbon dioxide.
III. Coal seam gas and petroleum gas are both fossil fuels.
Which of the above statements are correct?
I and II only
I and III only
II and III only
I, II and III
Reveal Answer
I and II only
While statements I and II are correct, statement III is also true because both coal seam gas and petroleum gas are formed from ancient organic matter, making them fossil fuels.
I and III only
While statements I and III are correct, statement II is also true because both gases are primarily composed of hydrocarbons, which produce carbon dioxide and water upon combustion.
II and III only
While statements II and III are correct, statement I is also true because both gases are mixtures of various hydrocarbons and other trace gases, rather than pure substances.
I, II and III
All three statements are correct. Both gases are mixtures of hydrocarbons, combust to produce carbon dioxide, and are classified as fossil fuels.
Calculate the concentration of cadmium ions in a saturated solution of cadmium(II) phosphate, , .
Reveal Answer
Let dissolve per litre
| Descriptor | Marks |
|---|---|
Calculates the concentration of ions to 3 significant figures | 4 |
Provides most relevant steps of the calculation | 3 |
Provides some relevant steps of the calculation | 2 |
Provides some relevant information | 1 |
None of the above | 0 |
The equation for a system at equilibrium is given below.
At 25 `C, the value of K for this equilibrium is .
Which of the following statements about this system is true? Increasing the
partial pressure of NO(g) will increase the yield of and will increase the rate of the forward reaction.
partial pressure of NO(g) will increase the yield of but will decrease the rate of the forward reaction.
temperature will increase the yield of but decrease the rate of the forward reaction.
temperature will increase the yield of and increase the rate of the forward reaction.
Reveal Answer
partial pressure of NO(g) will increase the yield of and will increase the rate of the forward reaction.
According to Le Chatelier's principle, increasing the partial pressure of a reactant () shifts the equilibrium toward the products, increasing the yield. Additionally, a higher concentration of reactants increases the frequency of collisions, thereby increasing the forward reaction rate.
partial pressure of NO(g) will increase the yield of but will decrease the rate of the forward reaction.
While increasing the partial pressure of a reactant does increase the yield, it also increases (rather than decreases) the reaction rate due to a higher frequency of molecular collisions.
temperature will increase the yield of but decrease the rate of the forward reaction.
Increasing temperature increases the kinetic energy of the molecules, which always leads to an increase in the reaction rate, not a decrease.
temperature will increase the yield of and increase the rate of the forward reaction.
The reaction forming is exothermic; therefore, increasing the temperature shifts the equilibrium toward the reactants (left), decreasing the yield of .
A partly filled water bottle is sealed and left on a bench in a room with a constant temperature. After several minutes, it is noted that the water level in the bottle remains constant. In the water bottle, the rate of evaporation is
less than the rate of condensation.
greater than the rate of condensation.
equal to the rate of condensation and equal to zero.
equal to the rate of condensation but not equal to zero.
Reveal Answer
less than the rate of condensation.
If the rate of evaporation were less than the rate of condensation, the amount of liquid water would increase, causing the water level to rise.
greater than the rate of condensation.
If the rate of evaporation were greater than the rate of condensation, the amount of liquid water would decrease, causing the water level to drop.
equal to the rate of condensation and equal to zero.
While the rates are equal, they are not zero because molecules are constantly escaping and returning to the liquid surface in a state of dynamic equilibrium.
equal to the rate of condensation but not equal to zero.
A constant water level in a closed system indicates dynamic equilibrium, where the rate of evaporation equals the rate of condensation, and both processes continue to occur simultaneously.
The reaction shows part of the contact process used to produce sulfuric acid.
The equilibrium constant () for this reaction at different temperatures is shown.
| Temperature (K) | Equilibrium constant, (mol ) |
|---|---|
| 298 | |
| 500 |
Deduce if the forward reaction is exothermic or endothermic. Explain your reasoning.
Reveal Answer
Exothermic
Increasing temperature decreases , indicating that the equilibrium shifts towards the reactants (endothermic) direction.
| Descriptor | Marks |
|---|---|
Determines forward reaction is exothermic | 1 |
Explains that the decrease in as temperature increases indicates endothermic direction is towards the reactants | 1 |
Calculate the equilibrium concentration of at 500 K given the equilibrium concentrations.
Concentration = _____ M (to three significant figures)
Reveal Answer
Concentration = M
| Descriptor | Marks |
|---|---|
Provides appropriate working | 1 |
Calculates | 1 |
Apply Le Châtelier’s principle to explain whether halving the reaction vessel’s volume at 500 K would affect the position of the equilibrium or the value of the equilibrium constant.
Reveal Answer
Halving the volume would double the pressure.
To reduce the pressure, the equilibrium would shift toward the product to reduce the number of molecules present.
However, due to the reactant decreasing the equilibrium constant remains unchanged.
| Descriptor | Marks |
|---|---|
Indicates that halving the volume doubles the pressure | 1 |
Explains that equilibrium will shift to reduce the number of molecules present to reduce pressure | 1 |
Explains that equilibrium will shift toward the product | 1 |
Explains why the equilibrium constant would not change | 1 |
Which is the correct expression for calculating the solubility (in ) of lead(II) iodide in a solution of NaI at ?
Reveal Answer
This option incorrectly assumes the iodide concentration is and fails to square the iodide concentration in the expression.
This option incorrectly assumes the iodide concentration from NaI is . NaI only produces one iodide ion per formula unit, so the initial is .
This option forgets to square the iodide concentration. The expression for is , so the denominator must be squared.
The expression is . In a NaI solution, . Therefore, the solubility .
Which of the following is not a characteristic of a system in dynamic equilibrium?
The mass of the reactants equals the mass of the products.
Reactants are forming products and products are forming reactants.
The rates of the forward and reverse reactions are equal.
The position of the equilibrium is affected by temperature.
Reveal Answer
The mass of the reactants equals the mass of the products.
This is the correct answer because it is not a characteristic of equilibrium. While the amounts of reactants and products remain constant at equilibrium, their masses or concentrations are rarely equal to each other.
Reactants are forming products and products are forming reactants.
This is a true characteristic of dynamic equilibrium. The system is "dynamic" precisely because both the forward and reverse reactions continue to occur.
The rates of the forward and reverse reactions are equal.
This is a true characteristic. The fundamental definition of dynamic equilibrium is that the forward and reverse reaction rates are exactly equal.
The position of the equilibrium is affected by temperature.
This is a true characteristic. According to Le Chatelier's principle, changing the temperature of a system at equilibrium will shift its position to favor either the endothermic or exothermic direction.
The combustion reaction between butane gas, , and oxygen gas, , is considered irreversible because
the forward reaction is exothermic.
the products are less stable than the reactants.
the rate of the reverse reaction is so slow that it can be ignored.
an unlimited supply of oxygen will favour the forward reaction.
Reveal Answer
the forward reaction is exothermic.
While combustion is highly exothermic, exothermicity alone does not make a reaction irreversible. Many reversible reactions have exothermic forward reactions.
the products are less stable than the reactants.
In a combustion reaction, the products ( and ) are actually more stable than the reactants, which is why the reaction releases energy.
the rate of the reverse reaction is so slow that it can be ignored.
A reaction is considered practically irreversible when the activation energy for the reverse reaction is so high that its rate is effectively zero. This means the products do not convert back into reactants under normal conditions.
an unlimited supply of oxygen will favour the forward reaction.
While adding a reactant like oxygen favors the forward reaction according to Le Chatelier's principle, this describes shifting an equilibrium rather than defining a reaction as irreversible.
Consider the following reversible reaction:
Which of the following statements describes the relative concentrations of reactants and products in this system when equilibrium is established in a closed vessel at 35 °C?
The concentrations of reactants and products will be equal.
There will be a greater concentration of products than reactants.
The reactant concentration will be greater than that of the products.
The concentrations of NOCl and NO will be double the concentration of .
Reveal Answer
The concentrations of reactants and products will be equal.
Equal concentrations of reactants and products do not generally occur at equilibrium, especially when the equilibrium constant is significantly different from 1.
There will be a greater concentration of products than reactants.
Because the equilibrium constant is much greater than 1 (), the equilibrium lies far to the right, meaning the formation of products is strongly favored.
The reactant concentration will be greater than that of the products.
A greater concentration of reactants than products would only be expected if the equilibrium constant was much less than 1, indicating a reactant-favored system.
The concentrations of NOCl and NO will be double the concentration of .
The coefficients in the balanced chemical equation dictate the stoichiometric ratio in which substances react and form, not their absolute concentrations at equilibrium.