QCAA Physics Quantum Theory

15 sample questions with marking guides and sample answers

Q10
2023
SCSA
4 marks
Q10
4 marks

Estimate the de Broglie wavelength for a standard men's basketball travelling at 10.0 m s1^{-1}.

Reveal Answer

Using de Broglie's equation,

λ=hmv\begin{align*} \lambda &= \frac{h}{mv} \end{align*}

Taking the mass of a standard men's basketball as approximately

m=0.62 kg\begin{align*} m &= 0.62\ \text{kg} \end{align*}

then

λ=6.63×1034(0.62)(10.0)=1.07×1034 m\begin{align*} \lambda &= \frac{6.63\times10^{-34}}{(0.62)(10.0)} \\ &= 1.07\times10^{-34}\ \text{m} \end{align*}

So the estimated de Broglie wavelength is approximately

λ1.1×1034 m\begin{align*} \lambda &\approx 1.1\times10^{-34}\ \text{m} \end{align*}
Marking Criteria
DescriptorMarks

Estimates mass of basketball

1

Substitutes mvmv for pp in equation (using 0.60 kg)

1

Calculates answer

1

2 significant figures

1
Q31
2025
NESA
5 marks
Q31
5 marks

Experiments have been carried out by scientists to investigate cathode rays.

Assess the contribution of the results of these experiments in developing an understanding of the existence and properties of electrons.

Reveal Answer

Experimental results and their interpretation have played an essential role in developing and understanding of both the existence and properties of electrons.

It was demonstrated that cathode rays could be deflected by an electric field in a manner consistent with negatively charged particles. This experiment also allowed the deduction that the cathode rays were not electromagnetic waves because the latter would not be deflected by an electric field.

The combined effect of changing the magnitudes of electric and magnetic fields through which the electrons passed was measured and from this the charge-to-mass ratio of the electron was calculated.

Marking Criteria
DescriptorMarks
  • Provides a comprehensive assessment of the experimental results
  • Relates the results to both existence and properties of electrons
5
  • Provides a sound assessment of the experimental results
  • Relates the results to the properties and/or existence of electrons
4
  • Outlines an experiment and/or results
  • Relates experimental results to the existence and/or properties of electrons
3
  • Outlines a relevant experiment or result
    OR
  • Relates an experimental result to the existence or property of electrons
2

Provides some relevant information

1

None of the above

0
Q5
2023
QCAA
Paper 2
4 marks
Q5
4 marks

Describe what happens when light is shone onto a metallic surface in the context of the photoelectric effect.

Reveal Answer

Light with energy equivalent to hfhf has the ability to produce photoelectrons from a metallic surface.

When the frequency of light is below the threshold frequency for the metallic surface, the light will be reflected with no transfer of energy.

When the frequency of light is above the threshold frequency for the metallic surface, the energy of the photons will be absorbed and photoelectrons with kinetic energy proportional to the excess energy will be released.

The intensity of incident light is proportional to the number of photoelectrons for frequencies greater than the threshold frequency.

Marking Criteria
DescriptorMarks

Identifies incident light has energy equivalent to hfhf

1

Describes transfer of energy when frequency of light is below the threshold frequency

1

Describes transfer of energy when frequency of light is above the threshold frequency

1

Identifies relationship between intensity of incident light and resultant photoelectrons

1
Q27
2025
NESA
3 marks
Q27
3 marks

Outline TWO ways in which Schrödinger's model of electron behaviour is different from electron behaviour in the atomic models of Rutherford and Bohr.

Reveal Answer

In contrast to Bohr's idea of fixed orbits, Schrdinger described orbitals as probabilities of electrons as being in particular locations.

Unlike Rutherford's model in which electrons were imagined as particles orbiting the nucleus, Schrdinger described the electrons as waves, based on the work of de Broglie.

Marking Criteria
DescriptorMarks

Outlines TWO ways in which Schrödinger's model differs from those of Rutherford and Bohr

3
  • Outlines ONE way in which Schrödinger's model differs from those of Rutherford and Bohr
    OR
  • Outlines TWO features of Schrödinger's model
2

Provides some relevant information

1

None of the above

0
Q6
2022
QCAA
Paper 1
1 mark
Q6
1 mark

After coherent light has been passed through a double slit, the observation of an interference pattern on a screen is explained by the

A

wave nature of light.

B

equal width of the slits.

C

discrete packets of photons.

D

distance from the slits to the screen.

Reveal Answer
A

wave nature of light.

Correct Answer

Interference is a fundamental property of waves where overlapping wavefronts add constructively or destructively; this experiment is the classic evidence for the wave nature of light.

B

equal width of the slits.

While slit width affects the diffraction envelope and contrast, the interference pattern itself is caused by wave superposition, which can occur even if the slits are not perfectly equal in width.

C

discrete packets of photons.

Discrete packets (photons) refer to the particle nature of light; if light behaved strictly as classical particles, it would form two distinct bands rather than an interference pattern.

D

distance from the slits to the screen.

The distance to the screen affects the spacing of the fringes (scale), but it is not the fundamental cause of the interference phenomenon itself.

Q17
2021
VCAA
1 mark
Q17
1 mark

Which one of the following is closest to the de Broglie wavelength of a 663 kg663 \text{ kg} motor car moving at 10 m s110 \text{ m s}^{-1}?

A

1037 m10^{-37} \text{ m}

B

1036 m10^{-36} \text{ m}

C

1035 m10^{-35} \text{ m}

D

1034 m10^{-34} \text{ m}

Reveal Answer
A

1037 m10^{-37} \text{ m}

Correct Answer

Correct. Using the de Broglie wavelength formula λ=hmv\lambda = \frac{h}{mv}, we calculate λ=6.63×1034 J s663 kg×10 m s1=1037 m\lambda = \frac{6.63 \times 10^{-34} \text{ J s}}{663 \text{ kg} \times 10 \text{ m s}^{-1}} = 10^{-37} \text{ m}.

B

1036 m10^{-36} \text{ m}

Incorrect. This result is off by a factor of 10, which would occur if the velocity was 1 m s11 \text{ m s}^{-1} instead of 10 m s110 \text{ m s}^{-1}.

C

1035 m10^{-35} \text{ m}

Incorrect. This answer is off by a factor of 100, likely due to a miscalculation of the momentum denominator mv=6630 kg m s1mv = 6630 \text{ kg m s}^{-1}.

D

1034 m10^{-34} \text{ m}

Incorrect. This is approximately the value of Planck's constant (6.63×1034 J s6.63 \times 10^{-34} \text{ J s}), which means the momentum mvmv was incorrectly treated as 1 kg m s11 \text{ kg m s}^{-1}.

Q8
2022
QCAA
Paper 1
1 mark
Q8
1 mark

Determine the wavelength of an electromagnetic wave with an energy of 2.4×10232.4 \times 10^{-23} J.

A

7.2×10157.2 \times 10^{-15} m

B

2.8×10112.8 \times 10^{-11} m

C

8.3×1038.3 \times 10^{-3} m

D

1.2×1021.2 \times 10^2 m

Reveal Answer
A

7.2×10157.2 \times 10^{-15} m

This incorrect value results from simply multiplying the energy by the speed of light (E×cE \times c), ignoring Planck's constant and the correct formula.

B

2.8×10112.8 \times 10^{-11} m

This answer is obtained by dividing Planck's constant by the energy (h/Eh/E) but neglecting to multiply by the speed of light (cc).

C

8.3×1038.3 \times 10^{-3} m

Correct Answer

Using the relationship λ=hcE\lambda = \frac{hc}{E}, substitute Planck's constant (h6.626×1034h \approx 6.626 \times 10^{-34} J\cdots) and the speed of light (c3.00×108c \approx 3.00 \times 10^8 m/s) to find λ8.3×103\lambda \approx 8.3 \times 10^{-3} m.

D

1.2×1021.2 \times 10^2 m

This value represents the wavenumber (1/λ1201/\lambda \approx 120 m1^{-1}), which is the reciprocal of the wavelength rather than the wavelength itself.

Q7
2023
QCAA
Paper 2
5 marks
Q7
5 marks

Discuss the nature of light by describing evidence from two key experiments.

Reveal Answer

Young's double slit experiment and black-body radiation both provide evidence for the behaviour of light.

In Young's double slit experiment, the interference patterns formed as light passed between the two slits demonstrates the wave nature of light.

In contrast, black-body radiation demonstrates the quantised nature of light as electrons can only absorb or emit energy in discrete amounts.

Therefore, light has some wave properties and some particle properties.

Marking Criteria
DescriptorMarks

Identifies evidence for the nature of light comes from Young's double slit experiment

1

Identifies evidence for the nature of light comes from black-body radiation

1

Describes evidence for wave nature of light

1

Describes evidence for photons

1

Concludes light has the properties of both waves and particles

1
Q32
2024
NESA
8 marks
Q32
8 marks

Many scientists have performed experiments to explore the interaction of light and matter.

Analyse how evidence from at least THREE such experiments has contributed to our understanding of physics.

Reveal Answer

Answers could include:

Reference to:

  • Black body radiation experiments and the development of quantum physics
  • Photoelectric experiments and the development of quantum physics
  • Spectroscopy experiments and the development of astrophysics and the atomic model
  • Polarisation experiments and the development of the wave nature of light
  • Interference and diffraction and the development of the wave model of light
  • Cosmic gamma rays and the development of theory of special relativity and/or the standard model.
Marking Criteria
DescriptorMarks
  • Provides a detailed analysis using evidence from at least THREE experiments investigating the interaction of light and matter
  • Provides a clear link between experimental evidence and greater understanding of physics
8
  • Provides analysis using evidence from experiments investigating the interaction of light and matter
  • Provides a link between experimental evidence and greater understanding of physics
7

The student response meets all criteria of the 5-mark band, and additionally meets the majority of criteria in the 7-mark band.

6
  • Provides evidence from experiments investigating the interaction of light and matter
  • Relates evidence to a greater understanding of physics
5

The student response meets all criteria of the 3-mark band, and additionally meets the majority of criteria in the 5-mark band.

4

Provides some information about evidence from an experiment AND/OR a link to physics

3

The student response meets all criteria of the 1-mark band, and additionally meets the majority of criteria in the 3-mark band.

2

Provides some relevant information

1

None of the above

0
Q14
2023
VCAA
6 marks
Q14

Neutrons are subatomic particles and, like electrons, they can exhibit both particle-like and wave-like behaviour. Ignore any relativistic effects.

A beam of neutrons that can be used for scientific experiments is produced by a nuclear research reactor.

The mass of a neutron is 1.67×1027 kg1.67 \times 10^{-27} \text{ kg}.

The de Broglie wavelength of the neutrons produced by the nuclear reactor is 3.02×1010 m3.02 \times 10^{-10} \text{ m}.

Q14a
2 marks

Calculate the speed of the neutrons.

Reveal Answer

λd=hmv\lambda_d = \frac{h}{mv}

3.02×1010=6.63×1034(1.67×1027)×v3.02 \times 10^{-10} = \frac{6.63 \times 10^{-34}}{(1.67 \times 10^{-27}) \times v}

v=1.3×103 m s1v = 1.3 \times 10^3 \text{ m s}^{-1}

Marking Criteria
DescriptorMarks

Shows correct substitution into the de Broglie wavelength formula, e.g. 3.02×1010=6.63×1034(1.67×1027)×v3.02 \times 10^{-10} = \frac{6.63 \times 10^{-34}}{(1.67 \times 10^{-27}) \times v}

1

Calculates the correct speed of 1.3×103 m s11.3 \times 10^3 \text{ m s}^{-1}

1
Q14b
2 marks

The neutron beam is sent through a crystal with an interatomic spacing of 3.62×1010 m3.62 \times 10^{-10} \text{ m}.

Would you expect to observe a diffraction pattern? Justify your answer.

Reveal Answer

The ratio of λw=0.83\frac{\lambda}{w} = 0.83. As this ratio is close to 1, we would expect to be able to observe a diffraction pattern.

Marking Criteria
DescriptorMarks

Calculates the ratio λw\frac{\lambda}{w} as 0.830.83 and identifies that it is close to 1

1

Concludes that a diffraction pattern is expected to be observed

1
Q14c
2 marks

Consider an electron beam with the same de Broglie wavelength as the neutron beam, 3.02×1010 m3.02 \times 10^{-10} \text{ m}.

Which will have the greater speed: an electron in the electron beam or a neutron in the neutron beam? Justify your answer.

Reveal Answer

The electron will have the greater speed.

λd=hmv\lambda_d = \frac{h}{mv}

The product of mass and velocity must remain constant for wavelength to remain constant, so if mass decreases, velocity must increase.

Marking Criteria
DescriptorMarks

States that the electron will have the greater speed

1

Provides correct reasoning based on the de Broglie wavelength formula, explaining that for a constant wavelength, the product of mass and velocity must remain constant, so a smaller mass requires a greater velocity

1
Q11
2022
QCAA
Paper 1
1 mark
Q11
1 mark

The maximum kinetic energy of an electron ejected from a metallic surface can be increased by

A

using a positively ionised metal.

B

using a metal with a larger work function.

C

increasing the intensity of the incident light.

D

decreasing the wavelength of the incident light.

Reveal Answer
A

using a positively ionised metal.

Using a positively ionised metal would increase the electrostatic attraction on the electrons, effectively increasing the energy required to escape and decreasing the kinetic energy.

B

using a metal with a larger work function.

According to the photoelectric equation Kmax=hνΦK_{max} = h\nu - \Phi, increasing the work function (Φ\Phi) reduces the remaining energy available for kinetic energy.

C

increasing the intensity of the incident light.

Increasing intensity increases the number of photons and ejected electrons (photocurrent), but does not change the energy of individual photons or the maximum kinetic energy of the electrons.

D

decreasing the wavelength of the incident light.

Correct Answer

Photon energy is inversely proportional to wavelength (E=hcλE = \frac{hc}{\lambda}). Decreasing the wavelength increases the incident photon energy, thereby increasing the maximum kinetic energy of the ejected electrons.

Q2
2023
QCAA
Paper 1
1 mark
Q2
1 mark

Photons are

A

gauge bosons that exhibit wave characteristics.

B

particles that can only travel in a medium.

C

mediators of the weak nuclear force.

D

leptons with no charge.

Reveal Answer
A

gauge bosons that exhibit wave characteristics.

Correct Answer

Photons are the gauge bosons responsible for the electromagnetic force and exhibit wave-particle duality, displaying properties of both waves and particles.

B

particles that can only travel in a medium.

Unlike mechanical waves (like sound), photons are electromagnetic radiation and can travel through a vacuum without requiring a physical medium.

C

mediators of the weak nuclear force.

Photons mediate the electromagnetic force, whereas the weak nuclear force is mediated by WW and ZZ bosons.

D

leptons with no charge.

Photons are bosons, not leptons; leptons are a different family of particles that includes electrons and neutrinos.

Q8
2023
QCAA
Paper 1
1 mark
Q8
1 mark

Incident light with a frequency of 1.70×10151.70\times10^{15} Hz is shone onto a metal surface with a work function of 1.00×10181.00\times10^{-18} J.

Determine the kinetic energy of a photoelectron ejected from the metal surface.

A

7.9×1017.9\times10^{-1} eV

B

1.7×10151.7\times10^{-15} eV

C

1.3×10191.3\times10^{-19} eV

D

2.0×10382.0\times10^{-38} eV

Reveal Answer
A

7.9×1017.9\times10^{-1} eV

Correct Answer

This is the correct answer. First, calculate the photon energy E=hf1.13×1018E = hf \approx 1.13 \times 10^{-18} J. Subtract the work function to find the kinetic energy in Joules (K=EΦ1.26×1019K = E - \Phi \approx 1.26 \times 10^{-19} J), then divide by 1.60×10191.60 \times 10^{-19} J/eV to convert to electron-volts.

B

1.7×10151.7\times10^{-15} eV

This option is incorrect. It appears to confuse the numerical value of the frequency (1.71.7) with the final energy, ignoring Planck's constant and the necessary unit conversions.

C

1.3×10191.3\times10^{-19} eV

This option represents the kinetic energy in Joules (1.3×10191.3 \times 10^{-19} J), not electron-volts. To obtain the correct answer in eV, you must divide this value by the elementary charge (1.60×10191.60 \times 10^{-19} J/eV).

D

2.0×10382.0\times10^{-38} eV

This value is extremely small and physically unrealistic for the kinetic energy of a photoelectron in this context. It likely results from an arithmetic error or incorrect formula application.

Q9
2021
QCAA
Paper 1
1 mark
Q9
1 mark

The Bohr atomic model describes an atom as

A

the smallest particle of any substance.

B

a small dense nucleus orbited by electrons.

C

electrons scattered throughout a sphere of positively charged fluid.

D

a small positive nucleus surrounded by negative electrons in set orbits of fixed energy.

Reveal Answer
A

the smallest particle of any substance.

This describes John Dalton's early atomic theory, which viewed atoms as indivisible spheres, rather than the internal structure proposed by Bohr.

B

a small dense nucleus orbited by electrons.

This describes Rutherford's planetary model. While similar, it fails to include Bohr's key innovation: that electrons are restricted to specific, quantized orbits.

C

electrons scattered throughout a sphere of positively charged fluid.

This describes J.J. Thomson's "Plum Pudding" model, which was disproved by Rutherford before Bohr developed his model.

D

a small positive nucleus surrounded by negative electrons in set orbits of fixed energy.

Correct Answer

The Bohr model refined the nuclear model by proposing that electrons move in specific, circular orbits (shells) with fixed, quantized energy levels around the nucleus.

Q15
2022
VCAA
1 mark
Q15
1 mark

Which one of the following best provides evidence of light behaving as a particle?

A

photoelectric effect

B

white light passing through a prism

C

diffraction of light through a single slit

D

interference of light passing through a double slit

Reveal Answer
A

photoelectric effect

Correct Answer

The photoelectric effect demonstrates that light energy is absorbed and emitted in discrete quantized packets called photons, providing direct evidence of its particle nature.

B

white light passing through a prism

White light passing through a prism demonstrates dispersion and refraction, which are phenomena explained by the wave nature of light and its varying wavelengths.

C

diffraction of light through a single slit

Diffraction is the bending of light as it passes through a slit, which is a classic characteristic of waves rather than particles.

D

interference of light passing through a double slit

Interference patterns are created by the superposition of overlapping waves, providing foundational evidence for the wave model of light.

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