QCAA Physics Alternative Sequence Linear motion and force
15 sample questions with marking guides and sample answers
To determine a value for acceleration due to gravity, a student dropped an object from a height equal to their eye-level and counted the time from release to impact. The student then conducted the experiment two more times.
To reduce the percentage error of the experimental value for acceleration due to gravity, the student should
use an object with a lower mass.
conduct more trials of the experiment.
increase the height from which the object is released.
use a stopwatch to measure the time from release to impact.
Reveal Answer
use an object with a lower mass.
Acceleration due to gravity is independent of an object's mass, so using a lighter or heavier object will not affect the experimental value or its percentage error.
conduct more trials of the experiment.
While conducting more trials reduces random error and improves the reliability of the average result, it does not decrease the percentage error inherent in the individual measurements themselves.
increase the height from which the object is released.
Increasing the drop height increases the total time of the fall. Since the absolute uncertainty in timing (like human reaction time) remains relatively constant, a larger measured time results in a significantly smaller percentage error.
use a stopwatch to measure the time from release to impact.
Although a stopwatch is more precise than counting, human reaction time (typically around ) still introduces a massive percentage error for a short drop from eye-level (which takes only about ).
Leptons do not experience the
The escape velocity from the surface of a planet, which has no atmosphere, is . A mass is launched at to the planet's surface at .
What will be the subsequent motion of the mass?
A circular orbit around the planet
An elliptical orbit around the planet
A parabolic trajectory, returning to land with velocity
A trajectory reaching zero velocity at an infinite distance
Reveal Answer
A circular orbit around the planet
A circular orbit requires a negative total energy and a launch parallel to the surface at a specific orbital velocity, which is less than the escape velocity.
An elliptical orbit around the planet
An elliptical orbit requires the total energy of the system to be negative, meaning the launch velocity must be strictly less than the escape velocity.
A parabolic trajectory, returning to land with velocity
While the trajectory is indeed a parabola, an object launched at or above escape velocity will overcome the planet's gravity and never return to land.
A trajectory reaching zero velocity at an infinite distance
At escape velocity, the total energy (kinetic plus gravitational potential) of the mass is exactly zero. Regardless of the outward launch angle, it will escape the planet's gravitational field and reach zero velocity at an infinite distance.
Harriet and Tom were investigating how the speed, , of a falling object varied with the distance, , it had fallen.
They dropped a small steel ball, initially at rest, from the third floor of their school building. The speed of the ball was measured at six positions as it fell.
Air resistance can be ignored.
Which one of the following graphs of their data would be expected to result in a straight line through the origin?
versus
versus
versus
versus
Reveal Answer
versus
The kinematic equation for an object falling from rest is , meaning is proportional to . A graph of versus would result in a curve, not a straight line.
versus
Using the kinematic equation with an initial velocity of , we get . This shows that is directly proportional to , which produces a straight line through the origin.
versus
Based on the equation , is directly proportional to , not . Plotting versus would result in a quadratic curve.
versus
Since is proportional to , would be proportional to . Plotting versus would not produce a straight line.
What is the final velocity of a object dropped from a height of ?
Reveal Answer
Incorrect. This value is too low and does not follow the kinematic equation .
Incorrect. This velocity is incorrect; remember that the final velocity of a dropped object is independent of its mass and depends only on height and gravity.
Incorrect. This is less than the actual final velocity calculated using .
Correct. Using the kinematic equation (where initial velocity is zero), the final velocity is , which rounds to . The mass of is extra information, as all objects fall at the same rate in a vacuum.
A object experiences an upwards force of as it falls through a viscous liquid in a cylindrical container.
Calculate the total work done on the object as it falls through the liquid (to 2 significant figures). Show your working.
Reveal Answer
Total work = 3.4 J (to 2 significant figures)
| Descriptor | Marks |
|---|---|
calculates the force due to gravity | 1 |
calculates the net force | 1 |
identifies the relationship between work and net force | 1 |
calculates the total work done | 1 |
Two satellites, and , are in stable circular orbits around the Earth. The radius of satellite 's orbit is three times that of satellite 's orbit. Both satellites have the same kinetic energy.
Show that the mass of is three times the mass of .
Reveal Answer
Substitute :
| Descriptor | Marks |
|---|---|
Shows all relevant steps to determine the mass ratio | 3 |
Makes progress towards determining mass ratio | 2 |
Provides some relevant information | 1 |
None of the above | 0 |
A four-wheeled cart starting at rest moves along a surface with a constant applied force of 55 N. It experiences a frictional force of 8 N on each wheel.
Determine the mass of the cart if it travels 60 m in 10 s. Show your working.
Reveal Answer
Total friction =
Since
Mass = (to the nearest whole number)
| Descriptor | Marks |
|---|---|
recognises scenario relates to the addition of vectors | 1 |
recognises scenario relates to linear motion with constant acceleration | 1 |
recognises scenario relates to Newton's second law | 1 |
calculates magnitude of net force | 1 |
calculates the acceleration of the cart | 1 |
determines the mass of the cart | 1 |
Two objects of equal mass, X and Y, move forward in the same direction. Object X starts behind object Y and moves faster. The two objects eventually collide, resulting in a combined object Z that continues to move forward at three times the original velocity of object Y.
Determine the final velocity of object Z.
Reveal Answer
This is incorrect. This value might result from an algebraic error when solving the conservation of momentum equation, such as solving for instead of .
Correct. Using conservation of momentum, , which simplifies to . Solving for gives , making the final velocity .
This is incorrect. This value represents the difference in initial velocities between object X and object Y, not the final velocity of the combined object Z.
This is incorrect. This value represents the initial velocity of object X (), rather than the final velocity of object Z.
Planet X has a mass 4 times that of Earth and a radius 3 times that of Earth. The escape velocity at the surface of Earth is 11.2 km s.
What is the escape velocity at the surface of planet X?
8.40 km s
9.70 km s
12.9 km s
14.9 km s
Reveal Answer
8.40 km s
Incorrect. This value is obtained by multiplying Earth's escape velocity by , incorrectly assuming escape velocity is proportional to .
9.70 km s
Incorrect. This value is obtained by multiplying Earth's escape velocity by , incorrectly assuming escape velocity is proportional to .
12.9 km s
Correct. Escape velocity is given by , meaning it is proportional to . For Planet X, km s.
14.9 km s
Incorrect. This value is obtained by multiplying Earth's escape velocity by , incorrectly assuming escape velocity is proportional to instead of .
The displacement, (in metres), of an object undergoing deceleration was recorded over time, (in seconds). An equation describing the trend was developed.
Given the uncertainties in the equation, what is a valid displacement of the object after seven seconds?
267 m
215 m
194 m
146 m
Reveal Answer
267 m
Incorrect. This value likely comes from ignoring the negative sign on the first term ( m), which falls far outside the valid uncertainty range of m to m.
215 m
Incorrect. This value is outside the valid displacement range of m to m, possibly resulting from an arithmetic error or misapplying the uncertainty values.
194 m
Incorrect. This value likely comes from forgetting to square the time variable ( m), placing it outside the valid range of m to m.
146 m
Correct. Substituting yields m. The value m is the only option that falls within this valid range of m to m.
A 20 kg object is placed on an inclined plane with a slope of 35°. If the object experiences a frictional force of 40 N and no additional applied force, calculate its acceleration down the inclined plane.
Reveal Answer
Correct. The net force is the component of gravity down the slope minus friction (). Dividing this net force ( N) by the mass ( kg) gives an acceleration of .
Incorrect. This value represents the acceleration of the object if there were no friction acting against it ().
Incorrect. This result comes from incorrectly using cosine instead of sine to find the component of gravity parallel to the slope ().
Incorrect. This calculates the acceleration if friction were incorrectly added to the gravitational force, acting in the same direction down the slope rather than opposing the motion.
Calculate the frequency of light that would be required to eject a photoelectron at a velocity of from a metal plate with a work function of 4.73 eV.
Hz
Hz
Hz
Hz
Reveal Answer
Hz
This is the threshold frequency, calculated using only the work function (), which ignores the additional energy needed for the kinetic energy of the ejected electron.
Hz
This frequency incorrectly corresponds to the difference between the kinetic energy and the work function, rather than their sum.
Hz
This frequency corresponds only to the kinetic energy of the electron (), ignoring the energy required to overcome the metal's work function.
Hz
The total photon energy is the sum of the work function and the electron's kinetic energy (). Dividing this total energy by Planck's constant gives the correct frequency.
Which example describes one of Newton’s laws of motion?
The acceleration of an object must always be uniform.
In the absence of a net force, an object maintains a constant velocity.
To an observer at rest, the length of a moving object appears shorter in the direction it is moving.
The force of attraction between each pair of point particles is inversely proportional to the square of the distance between them.
Reveal Answer
The acceleration of an object must always be uniform.
Incorrect. Newton's second law () shows that acceleration depends on the net force, which can change over time, meaning acceleration does not have to be uniform.
In the absence of a net force, an object maintains a constant velocity.
Correct. This accurately describes Newton's first law of motion, also known as the law of inertia, where an object's velocity remains constant unless acted upon by a net external force.
To an observer at rest, the length of a moving object appears shorter in the direction it is moving.
Incorrect. This describes length contraction, a principle from Einstein's theory of special relativity, not classical Newtonian mechanics.
The force of attraction between each pair of point particles is inversely proportional to the square of the distance between them.
Incorrect. This describes Newton's law of universal gravitation, which is a separate physical principle from his three laws of motion.
Light with a wavelength of 341 nm is shone onto a potassium metal plate in a photoelectric cell, causing a photocurrent to flow. The work function of potassium is 2.30 eV. Calculate the maximum speed of the electrons emitted by the plate.
Reveal Answer
Using photoelectric effect equation:
Convertine eV to Joules:
Calculating energy of incoming photon:
Calculating kinetic energy of electron:
Velocity of electron:
| Descriptor | Marks |
|---|---|
Uses photoelectric effect equation | 1 |
Converts eV to Joules | 1 |
Calculates the energy of incoming photon. | 1 |
Calculates kinetic energy of electron | 1 |
Calculates the velocity of the electron | 1 |