QCAA Physics Alternative Sequence Electrical circuits

This value represents the charge of three elementary charges (like protons or electrons), not the total macroscopic charge calculated using the formula $Q = I \times t$.

This incorrect answer comes from dividing the current by the time in seconds ($3 / 180$), rather than multiplying them.

This results from multiplying the current by the time in minutes ($3 \times 3 = 9$), forgetting the crucial step of converting time to standard SI units (seconds).

While transformers are indeed used to step up the voltage, this explains how high voltages are achieved, not why they are beneficial for long-distance transmission.

While high voltages are used to transmit large amounts of power, the fundamental reason for stepping up the voltage is to minimize power loss during transmission, not just to increase capacity.

The resistance of a transmission line is determined by its physical properties (material, length, and cross-sectional area), not by the voltage applied to it.

Capacitance measures a component's ability to store electrical charge ($C = Q/V$), not the energy available for charges actively moving through a circuit.

Resistance is the opposition to the flow of electric current, which dissipates energy rather than measuring the energy available for the charges.

Current is the rate of flow of electric charge ($I = Q/t$), measuring how many charges move past a point per second rather than the energy they carry.

The ratio of voltage to current ($V/I$) defines electrical resistance, not power. Power is calculated as the product of voltage and current ($P = VI$).

The ratio of useful work performed to total energy expended defines the efficiency of a system, not power dissipation.

This describes the Law of Conservation of Energy, which states total energy input equals total energy output. Power dissipation is the rate of energy loss, not the total energy balance.

Incorrect. This value does not follow the formula for electrical work ($W = VIt$) and likely results from an arbitrary combination of the given numbers.

Incorrect. This value represents the power of the appliance ($P = VI = 357 \text{ W}$), not the total work done. Work requires multiplying power by time.

Incorrect. This calculation fails to convert time to standard SI units (seconds). Using $5.0 \text{ minutes}$ directly in the formula yields $1785 \text{ J}$, which is incorrect.

This is incorrect because Volts (V) measure electric potential difference, which is equivalent to Joules per Coulomb (J C$^{-1}$), not Coulombs per second.

This is incorrect because Ohms ($\Omega$) measure electrical resistance, which is equivalent to Volts per Ampere (V A$^{-1}$).

This is incorrect because Watts (W) measure power, which is the rate of energy transfer and is equivalent to Joules per second (J s$^{-1}$).

This value represents the total current in the circuit ($I = V/R = 8.0 / 6.0 \approx 1.3 \text{ A}$), not the total power.

This would be the total power if the resistors were connected in parallel ($R_{eq} = 1.44 \ \Omega$), but the problem states they are in series.

This is the result of multiplying voltage by resistance ($V \times R$), which does not give power. Power must be calculated using $P = V^2/R$ or $P = VI$.