QCAA Mathematical Methods Differentiation of exponential and logarithmic functions

5 sample questions with marking guides and sample answers

Q2
2024
QCAA
Paper 1
1 mark
Q2
1 mark

Determine dydx\frac{dy}{dx} for the function y=esin(x)y = e^{\sin(x)}

A

cos(x)esin(x)\cos(x) e^{\sin(x)}

B

sin(x)ecos(x)\sin(x) e^{\cos(x)}

C

esin(x)e^{\sin(x)}

D

ecos(x)e^{\cos(x)}

Q9
2023
QCAA
Paper 2
1 mark
Q9
1 mark

If f(x)=e3x(x+1)2f(x) = e^{3x}(x+1)^2 and f(x)=ae3x(x+1)f'(x) = ae^{3x}(x+1), determine the expression for aa.

A

3x+53x+5

B

3x+33x+3

C

5x+55x+5

D

5x+35x+3

Q13
2024
QCAA
Paper 2
8 marks
Q13

The number of termites in a particular nest can be modelled by N(t)=A2+etN(t) = \frac{A}{2 + e^{-t}}, where AA is a constant and tt represents time (months) since the nest first became a visible mound above ground level.
It is estimated that when the mound first became visible, the population was 3×1053 \times 10^5 termites.

Q13a
1 mark

Determine the value of AA.

Q13b
2 marks

Determine the number of termites in the nest half a year after the mound became visible.

Q13c
2 marks

Determine the time in months after the mound became visible for the initial population to increase by 130 000 termites. Express the time as a decimal.

Q13d
2 marks

Develop a formula for the rate of change in the number of termites at any time after the mound became visible. Express your formula as a fraction.

Q13e
1 mark

Determine the rate of change in the number of termites five months after the mound became visible.

Q13
2022
QCAA
Paper 1
9 marks
Q13a
1 mark

Determine the derivative of f(x)=3e2x+1f(x) = 3e^{2x+1}

Q13b
3 marks

Given that g(x)=ln(x)xg(x) = \frac{\ln(x)}{x}, determine the simplest value of g(e)g'(e).

Q13c
5 marks

Determine the second derivative of h(x)=xsin(x)h(x) = x\sin(x). (Give your answer in simplest form.)

Q14
2024
QCAA
Paper 2
6 marks
Q14

A football coach offered a 12-day intensive training clinic. During the clinic, the height that each player could kick a football was monitored.
One player's kick heights could be modelled by H(t)=log10(10t+10)+5H(t) = \log_{10}(10t + 10) + 5, 0t120 \le t \le 12, where H(t)H(t) is vertical height (m) and tt is the time (days) spent in training.

Q14a
1 mark

Determine the initial height that the player could kick the ball.

Q14b
1 mark

Determine the training time needed for the player to be able to kick the ball to a height of 7 m.

Q14c
2 marks

Determine the overall improvement in kick height achieved by completing the clinic.

Q14d
1 mark

Determine the rate of change in kick height when t=1.5t = 1.5 days.

Q14e
1 mark

Determine the training time (as a decimal) when the rate of change in kick height is 0.09 m/day.

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