QCAA General Mathematics Earth geometry and time zones

15 sample questions with marking guides and sample answers

Q5
2024
QCAA
Paper 2
6 marks
Q5
6 marks

A flying doctor coordinator allocates a plane from each of three airbases, A, B and C, to fly to one of three sites, P, Q and R, to provide medical care. Distances (km) are shown in the table.

 P (2828^\circ S 136136^\circ E)QR (2020^\circ S 147147^\circ E)
A (2020^\circ S 136136^\circ E)xx600yy
B445485340
C9801170770

Determine the optimal allocation for each plane and the minimum total distance flown.

Reveal Answer

Calculate xx (distance from A to P):
Angular distance =2820=8= 28^\circ - 20^\circ = 8^\circ
D=111.2×8890D = 111.2 \times 8^\circ \approx 890 km

Calculate yy (distance from A to R):
Angular distance =147136=11= 147^\circ - 136^\circ = 11^\circ
D=111.2×cos20×111149D = 111.2 \times \cos 20^\circ \times 11^\circ \approx 1149 km

Row reduction:
[290054910514502104000]\begin{bmatrix} 290 & 0 & 549 \\ 105 & 145 & 0 \\ 210 & 400 & 0 \end{bmatrix}

Column reduction:
[1850549014501054000]\begin{bmatrix} 185 & 0 & 549 \\ 0 & 145 & 0 \\ 105 & 400 & 0 \end{bmatrix}

Number of lines needed to cover all zeros = number of tasks (3=33 = 3), so allocate planes.
For minimum distance, the plane allocation is airbase A to site Q, airbase B to site P and airbase C to site R.

Minimum total distance flown =600+445+770= 600 + 445 + 770
=1815= 1815 km

Marking Criteria
DescriptorMarks

correctly calculates distance x in kilometres

1

correctly calculates distance y in kilometres

1

reduces each row

1

reduces each column

1

identifies optimal allocation for each plane

1

determines minimum total distance flown

1
Q14
2022
QCAA
Paper 1
1 mark
Q14
1 mark

A rugby fan in Perth (Australia) plans to watch a live match played in New Zealand next winter. The time zone for Perth is UTC +8. The time zone for New Zealand is UTC +13 in winter and UTC +12 in summer.

If the match is played at 6:30 pm New Zealand time, what time will the match be viewed in Perth?

A

1:30 pm

B

2:30 pm

C

10:30 pm

D

11:30 pm

Reveal Answer
A

1:30 pm

Correct Answer

According to the prompt, New Zealand is UTC+13 in winter and Perth is UTC+8. The difference is 138=513 - 8 = 5 hours. Since Perth is west of New Zealand, it is behind in time, so you subtract 5 hours: 6:30 pm5 hours=1:30 pm6:30 \text{ pm} - 5 \text{ hours} = 1:30 \text{ pm}.

B

2:30 pm

This option assumes a 4-hour time difference (UTC+12 vs UTC+8). However, the question explicitly states that New Zealand is UTC+13 during the winter, creating a 5-hour difference.

C

10:30 pm

This result implies adding 4 hours to the time. Since Perth is west of New Zealand, the time there is earlier, so the time difference must be subtracted, not added.

D

11:30 pm

This calculation incorrectly adds the 5-hour time difference to the scheduled time. Because Perth is in a time zone behind New Zealand (UTC+8 vs UTC+13), you must subtract the difference.

Q17
2020
QCAA
Paper 1
3 marks
Q17
3 marks

Calculate the distance along the parallel of latitude between Mount Gambier, South Australia (375037^\circ 50' S, 14047140^\circ 47' E) and Bairnsdale, Victoria (375037^\circ 50' S, 14737147^\circ 37' E) to the nearest kilometre.

Reveal Answer

Distance is east / west
\therefore distance = 111.2×cosθ×111.2 \times \cos \theta \times angular dist.

angular dist. = 1473714047147^\circ 37' - 140^\circ 47'
=650= 6^\circ 50'

distance = 111.2×cosθ×111.2 \times \cos \theta \times angular dist.
=111.2×cos(3750)×(650)= 111.2 \times \cos(37^\circ 50') \times (6^\circ 50')
=600.14= 600.14

It is approximately 600 km between Mount Gambier and Bairnsdale.

Marking Criteria
DescriptorMarks

Correctly calculates the angular distance

1

Provides evidence of substituting into the appropriate distance rule

1

Calculates distance to the nearest km

1
Q25
2021
QCAA
Paper 1
4 marks
Q25

A conference is being held in Singapore (UTC +8).

Q25a
2 marks

A conference attendee got a flight from Brisbane (UTC +10) at 10:30 am Brisbane time on Monday 7 December.

If the flight from Brisbane to Singapore took 7 hours and 40 minutes, determine the time, day and date in Singapore when the flight lands.

Reveal Answer

Depart Brisbane 10:30 Mon 7/12
Flight: + 7:40
Arrive Singapore 18:10
UTC correction 2:00-2:00
=16:10= 16:10

4:10 pm in Singapore on Mon 7/12

Marking Criteria
DescriptorMarks

correctly adds the flight time

1

correctly determines the local time, day and date in Singapore

1
Q25b
2 marks

A conference attendee from Dubai (UTC +4) arrived in Singapore at 5 pm Singapore time on Monday 7 December.

If the flight from Dubai to Singapore took 8 hours and 25 minutes, determine the time, day and date in Dubai when the flight departed.

Reveal Answer

Arrive Singapore 17:00 Mon 7/12
Flight: 8:25- 8:25
Depart Dubai 8:35
UTC correction 4:00-4:00
=4:35= 4:35

4:35 am in Dubai on Mon 7/12

Marking Criteria
DescriptorMarks

correctly subtracts the flight time

1

correctly determines the local time, day and date in Dubai

1
Q1
2024
QCAA
Paper 1
1 mark
Q1
1 mark

A location with coordinates (28° N 16° W) is positioned

A

28° north of the prime meridian and 16° west of the equator.

B

28° north of the equator and 16° west of the prime meridian.

C

28° north of the International Date Line and 16° west of the equator.

D

28° north of the equator and 16° west of the International Date Line.

Reveal Answer
A

28° north of the prime meridian and 16° west of the equator.

This option reverses the reference lines; latitude (North/South) is measured from the equator, and longitude (East/West) is measured from the prime meridian.

B

28° north of the equator and 16° west of the prime meridian.

Correct Answer

Latitude (28° N) measures distance north of the equator, and longitude (16° W) measures distance west of the prime meridian.

C

28° north of the International Date Line and 16° west of the equator.

Latitude is measured relative to the equator, not the International Date Line, and longitude is measured relative to the prime meridian, not the equator.

D

28° north of the equator and 16° west of the International Date Line.

While the latitude reference is correct, longitude is measured relative to the prime meridian (00^\circ), not the International Date Line (approx. 180180^\circ).

Q7
2024
QCAA
Paper 2
7 marks
Q7
7 marks

A non-stop flight departs Sydney (UTC +10) at 9:50 pm Tuesday local time and arrives in Los Angeles (UTC –8) at 6:50 pm Tuesday local time. Flight speed is assumed to be constant.

Determine the local time and day in Sydney when the flight distance travelled is 4828 km, with 7242 km remaining.

Reveal Answer

Total flight distance from Sydney to Los Angeles
=4828+7242=12070= 4828 + 7242 = 12\,070 km
Time difference between Sydney (UTC +10) and Los Angeles (UTC -8)
=+10(8)=18= +10 - (-8) = 18 hours
\therefore Sydney is 18 hours ahead of Los Angeles.

Local time and day in Sydney when flight arrives in Los Angeles
=6:50= 6:50 pm Tuesday +18+ 18 h
=12:50= 12:50 pm Wednesday

Total flight duration from Sydney to Los Angeles
=12:50= 12:50 pm Wednesday 9:50- 9:50 pm Tuesday
=15= 15 hours

Proportion of total flight distance when 4828 km travelled
=482812070×100= \frac{4828}{12070} \times 100
=40%= 40\%

Flight duration when 4828 km travelled
=40%= 40\% of 15 h
=6= 6 hours

Local time and day in Sydney when 4828 km travelled
=9:50= 9:50 pm Tuesday +6+ 6 h
=3:50= 3:50 am Wednesday

Marking Criteria
DescriptorMarks

correctly calculates the total flight distance and the absolute time difference between locations

1

applies relative time difference to Los Angeles arrival time (or Sydney departure time) to determine local time and day in other location

1

calculates total flight duration

1

shows use of appropriate method to determine flight duration

1

determines flight duration when 4828 km travelled

1

determines local time and day in Sydney when 4828 km travelled

1

shows logical organisation, communicating key steps

1
Q12
2025
QCAA
Paper 1
1 mark
Q12
1 mark

Determine the distance between the two locations: X (18.7° N 15.3° W) and Y (12.4° S 15.3° W).

A

676 km

B

701 km

C

3336 km

D

3458 km

Reveal Answer
A

676 km

This value is incorrect and does not correspond to the proper calculation for the distance between these two coordinates.

B

701 km

This would be the distance if both locations were in the same hemisphere, which would involve subtracting the latitudes (18.712.4=6.318.7^\circ - 12.4^\circ = 6.3^\circ) instead of adding them.

C

3336 km

This distance is incorrect and results from a miscalculation of the latitude difference or the Earth's radius.

D

3458 km

Correct Answer

Since the locations share the same longitude but are in opposite hemispheres, you add their latitudes to find the total difference (18.7+12.4=31.118.7^\circ + 12.4^\circ = 31.1^\circ). Multiplying this by the average distance per degree of latitude (111.2\approx 111.2 km) gives approximately 3458 km.

Q1
2021
QCAA
Paper 2
4 marks
Q1
4 marks

A sailor anchors her yacht near Rocky Island at 14° 52' S, 145° 29' E. Her yacht is at the same latitude as her home, but the sun rises exactly 1 hour and 13 minutes later at home.

What are the coordinates of her home?

Reveal Answer

Home latitude =1452 S= 14^{\circ}52' \text{ S}

Change time difference to angular difference

Angle =11360×15= 1\frac{13}{60} \times 15^{\circ}
=18.25= 18.25^{\circ}

Home longitude =145291815= 145^{\circ}29' - 18^{\circ}15'
=12714= 127^{\circ}14'

Home coordinates are 1452 S,12714 E14^{\circ}52' \text{ S}, 127^{\circ}14' \text{ E}

Marking Criteria
DescriptorMarks

correctly identifies the latitude

1

correctly determines the angle

1

subtracts angle from longitude in same format

1

determines longitude

1
Q15
2022
QCAA
Paper 1
1 mark
Q15
1 mark

The actual distance between two cities has been correctly calculated as 556 km. The latitude and longitude respectively of these two cities could be

A

22^\circ N 104104^\circ W and 33^\circ S 104104^\circ W.

B

22^\circ N 104104^\circ W and 33^\circ N 104104^\circ W.

C

2525^\circ N 150150^\circ E and 3030^\circ S 150150^\circ E.

D

2525^\circ N 145145^\circ E and 2525^\circ N 150150^\circ E.

Reveal Answer
A

22^\circ N 104104^\circ W and 33^\circ S 104104^\circ W.

Correct Answer

These cities share the same longitude, so the distance is determined by the latitude difference of 55^\circ (22^\circ N to 33^\circ S). Since 11^\circ of latitude corresponds to approximately 111.2111.2 km, the total distance is 5×111.25565 \times 111.2 \approx 556 km.

B

22^\circ N 104104^\circ W and 33^\circ N 104104^\circ W.

The cities share the same longitude, but the latitude difference is only 11^\circ (33^\circ N minus 22^\circ N). This results in a distance of approximately 111111 km, which is far less than 556556 km.

C

2525^\circ N 150150^\circ E and 3030^\circ S 150150^\circ E.

The latitude difference between these points is 5555^\circ (2525^\circ N plus 3030^\circ S). Multiplying by 111111 km per degree yields a distance of over 6,0006,000 km.

D

2525^\circ N 145145^\circ E and 2525^\circ N 150150^\circ E.

These cities share the same latitude, so the distance is calculated using the longitude difference (55^\circ) multiplied by the cosine of the latitude. The result is approximately 5×111×cos(25)5035 \times 111 \times \cos(25^\circ) \approx 503 km.

Q10
2024
QCAA
Paper 1
1 mark
Q10
1 mark

The local time in Osaka (35° N 135° E) is two hours ahead of the local time in Phnom Penh. What is the most likely longitude for Phnom Penh?

A

5° N

B

65° N

C

105° E

D

165° E

Reveal Answer
A

5° N

This value represents latitude (55^\circ N), but local time differences are determined by longitude (East/West coordinates).

B

65° N

This is a latitude coordinate (6565^\circ N). Time zones and local time are calculated based on longitude, not latitude.

C

105° E

Correct Answer

Earth rotates 1515^\circ per hour. Since Osaka is 2 hours ahead, Phnom Penh must be 3030^\circ (2×152 \times 15^\circ) to the west: 135 E30=105 E135^\circ \text{ E} - 30^\circ = 105^\circ \text{ E}.

D

165° E

This longitude is 3030^\circ east of Osaka (135+30135^\circ + 30^\circ), which would make the local time there 2 hours ahead of Osaka, rather than Osaka being ahead.

Q16
2023
QCAA
Paper 1
3 marks
Q16
3 marks

If it is 2:00 am local time in town A (3030^\circ N 9090^\circ W), calculate the local time in town B (2626^\circ S 120120^\circ E).

Reveal Answer

Angular difference = 90+120=21090^\circ + 120^\circ = 210^\circ
Time difference = 21015/h=14\frac{210^\circ}{15^\circ / h} = 14 hours
Town B is east of town A, so town B is 14 hours ahead of town A.
Local time in town B = 2:00 am + 14 hours = 4:00 pm

Marking Criteria
DescriptorMarks

correctly determines the angular difference

1

determines absolute time difference between town A and town B

1

determines local time in town B

1
Q23
2020
QCAA
Paper 1
4 marks
Q23
4 marks

A plane leaves Brisbane (UTC +10) at 10:45 pm on Monday and takes 14 hours and 35 minutes to fly to Dubai (UTC +4).

Determine the local time and day in Dubai when the plane arrives.

Reveal Answer

Depart Brisbane 22:45 Monday Brisbane time
Travel +14:35
Arrive Dubai 37:20 Monday
next day - 24:00
13:20 Tuesday
UTC correction - 6:00
7:20 am on Tuesday in Dubai

Marking Criteria
DescriptorMarks

Correctly adds travel time

1

Calculates arrival time from Brisbane's perspective

1

Correctly subtracts time difference

1

Calculates arrival time and day from Dubai's perspective

1
Q16
2025
QCAA
Paper 1
3 marks
Q16
3 marks

Determine the time and day in Santa Cruz (GMT -8) when it is 2:00 pm Monday in Nagano (GMT +9).

Reveal Answer

Time difference = (+9) - (-8)
= 17 hours behind

Time in Santa Cruz
= Time in Nagano - 17 hours
= 2:00 pm Monday - 12 hours - 5 hours
= 2:00 am Monday - 5 hours

The time in Santa Cruz is 9:00 pm.

The day in Santa Cruz is Sunday.

Marking Criteria
DescriptorMarks

correctly provides mathematical reasoning or working to support the answer

1

determines time in Santa Cruz

1

determines day in Santa Cruz

1
Q11
2025
QCAA
Paper 1
1 mark
Q11
1 mark

In summer, New Zealand (GMT +12) uses daylight saving time, which is one hour ahead of New Zealand standard time. Western Australia (GMT +8) does not use daylight saving time.

When it is midday in summer in New Zealand, what is the time in Western Australia?

A

7 am

B

9 am

C

3 pm

D

5 pm

Reveal Answer
A

7 am

Correct Answer

New Zealand summer time is GMT +13 (GMT +12 plus 1 hour for daylight saving). Western Australia is GMT +8, which is 5 hours behind New Zealand. Therefore, midday (12:00 pm) minus 5 hours is 7:00 am.

B

9 am

This assumes a 3-hour time difference, which incorrectly ignores daylight saving time and miscalculates the standard time zones.

C

3 pm

This incorrectly assumes Western Australia is 3 hours ahead of New Zealand, rather than being behind.

D

5 pm

This incorrectly assumes Western Australia is 5 hours ahead of New Zealand, rather than 5 hours behind.

Q10
2021
QCAA
Paper 1
1 mark
Q10
1 mark

City A is located at 5555^\circ N, 120120^\circ E and City B is located at 4040^\circ N, 165165^\circ E. The sun will rise in City A approximately

A

1 hour before it rises in City B.

B

1 hour after it rises in City B.

C

3 hours before it rises in City B.

D

3 hours after it rises in City B.

Reveal Answer
A

1 hour before it rises in City B.

This is incorrect because the longitude difference is 4545^\circ, which corresponds to a 3-hour time difference (45/1545^\circ / 15^\circ per hour), not 1 hour. Furthermore, City A is west of City B, so the sun rises later, not before.

B

1 hour after it rises in City B.

While the direction (after) is correct, the time calculation is wrong. The difference in longitude is 4545^\circ, which results in a 3-hour difference (45/1545^\circ / 15^\circ per hour), not 1 hour.

C

3 hours before it rises in City B.

This is incorrect because of the direction. Although the 3-hour difference is correct, City A (120120^\circ E) is west of City B (165165^\circ E), meaning the sun rises in City A later than in City B.

D

3 hours after it rises in City B.

Correct Answer

The longitude difference between the cities is 165120=45165^\circ - 120^\circ = 45^\circ. Since the Earth rotates 1515^\circ per hour, the time difference is 3 hours. Because City A is west of City B, the sun rises there 3 hours later.

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