How many NESA Physics questions cover Quantum Mechanical Nature of the Atom?

AusGrader has 46 NESA Physics questions on Quantum Mechanical Nature of the Atom, all with instant AI grading and detailed marking feedback.

NESA (HSC) Physics — Quantum Mechanical Nature of the Atom Questions & Answers | AusGrader

Q14

2024

NESA

1 mark

Q14

1 mark

The velocity of a proton ( $\text{}^1_1\text{H}$ ) is twice the velocity of an alpha particle ( $\text{}^4_2\text{He}$ ). The proton has a de Broglie wavelength of $\lambda$ .

What is the de Broglie wavelength of the alpha particle?

A

$\frac{\lambda}{8}$

B

$\frac{\lambda}{2}$

C

$2\lambda$

D

$8\lambda$

Q7

2023

NESA

1 mark

Q7

1 mark

A proton and a neutron travel at the same speed.

Which statement correctly explains the difference between their de Broglie wavelengths?

A

The proton has a longer wavelength because its mass is greater.

B

The proton has a shorter wavelength because its mass is smaller.

C

The neutron has a shorter wavelength because its mass is greater.

D

The neutron has a longer wavelength because its mass is smaller.

Q27

2025

NESA

3 marks

Q27

3 marks

Outline TWO ways in which Schrödinger's model of electron behaviour is different from electron behaviour in the atomic models of Rutherford and Bohr.

In contrast to Bohr's idea of fixed orbits, Schrdinger described orbitals as probabilities of electrons as being in particular locations.

Unlike Rutherford's model in which electrons were imagined as particles orbiting the nucleus, Schrdinger described the electrons as waves, based on the work of de Broglie.

Marking Criteria

Descriptor	Marks
Outlines TWO ways in which Schrödinger's model differs from those of Rutherford and Bohr	3
Outlines ONE way in which Schrödinger's model differs from those of Rutherford and Bohr OR Outlines TWO features of Schrödinger's model	2
Provides some relevant information	1
None of the above	0

Q23

2023

NESA

7 marks

Q23

The James Webb Space Telescope (JWST) has a mass of $6.1 \times 10^{3}\ \text{kg}$ and orbits the Sun at a distance of approximately $1.52 \times 10^{11}\ \text{m}$ .

Q23a

2 marks

The Sun has a mass of $1.99 \times 10^{30}\ \text{kg}$ .

Calculate the magnitude of gravitational force the Sun exerts on the JWST.

\begin{align*} F &= \frac{GMm}{r^2}\\ &= \frac{6.67 \times 10^{-11} \times 1.99 \times 10^{30} \times 6.1 \times 10^3}{(1.52 \times 10^{11})^2}\\ &= 35 \text{ N} \end{align*}

Marking Criteria

Descriptor	Marks
Calculates the magnitude of gravitational force	2
Provides some relevant information	1
None of the above	0

Q23b

3 marks

The telescope is sensitive to wavelengths from $6.0 \times 10^{-7}\ \text{m}$ to $2.8 \times 10^{-5}\ \text{m}$ .

What is the minimum photon energy that it can detect?

\begin{align*} E &= hf\\ &= \frac{hc}{\lambda}\\ &= \frac{6.626 \times 10^{-34} \times 3 \times 10^8}{2.8 \times 10^{-5}}\\ &= 7.1 \times 10^{-21} \text{ J} \end{align*}

Marking Criteria

Descriptor	Marks
Calculates the minimum photon energy the telescope can detect	3
Provides some correct steps in calculating the minimum photon energy	2
Provides some relevant information	1
None of the above	0

Q23c

2 marks

The JWST observed an exoplanet emitting a peak wavelength of $1.14 \times 10^{-5}\ \text{m}$ .

Calculate the temperature of the exoplanet.

\begin{align*} \lambda &= \frac{b}{T}\\ T &= \frac{b}{\lambda}\\ &= \frac{2.898 \times 10^{-3}}{1.14 \times 10^{-5}}\\ &= 254 \text{ K} \end{align*}

Marking Criteria

Descriptor	Marks
Calculates the temperature of the exoplanet	2
Provides some relevant information	1
None of the above	0

Q10

2023

SCSA

4 marks

Q10

4 marks

Estimate the de Broglie wavelength for a standard men's basketball travelling at 10.0 m s $^{-1}$ .

Using de Broglie's equation,

\begin{align*} \lambda &= \frac{h}{mv} \end{align*}

Taking the mass of a standard men's basketball as approximately

\begin{align*} m &= 0.62\ \text{kg} \end{align*}

then

\begin{align*} \lambda &= \frac{6.63\times10^{-34}}{(0.62)(10.0)} \\ &= 1.07\times10^{-34}\ \text{m} \end{align*}

So the estimated de Broglie wavelength is approximately

\begin{align*} \lambda &\approx 1.1\times10^{-34}\ \text{m} \end{align*}

Marking Criteria

Descriptor	Marks
Estimates mass of basketball	1
Substitutes $mv$ for $p$ in equation (using 0.60 kg)	1
Calculates answer	1
2 significant figures	1

NESA Physics Quantum Mechanical Nature of the Atom

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