NESA Physics Applications of the Motor Effect

1 sample question with marking guides and sample answers · Avg. score: 0%

Q12
2025
VCAA
7 marks
Q12

Denzil is using a demonstration hand-cranked generator.

A schematic diagram of the generator is shown in Figure 17. The generator contains a rectangular coil with side lengths of 5.0 cm and 2.5 cm, consisting of 20 turns of insulated copper wire. The coil is rotated between two bar magnets that provide a field strength of 0.60 T between the magnets.

Denzil rotates the coil at a frequency of 50 Hz.

Q12a
1 mark

State why the flux through the coil changes as the coil rotates.

Reveal Answer

The flux through the coil is determined by the angle between the plane of the coil and the magnetic field.

Marking Criteria
DescriptorMarks

States that the angle or orientation between the plane of the coil and the magnetic field changes

1
Q12b
1 mark

Show that the change in flux as the coil rotates from a horizontal to a vertical position is 7.5×104 Wb7.5 \times 10^{-4} \text{ Wb}.

Reveal Answer

Δϕ=BA\Delta\phi = BA

Δϕ=0.60×(0.05×0.025)\Delta\phi = 0.60 \times (0.05 \times 0.025)

Δϕ=7.5×104 Wb\Delta\phi = 7.5 \times 10^{-4} \text{ Wb}

Marking Criteria
DescriptorMarks

Demonstrates correct substitution into the magnetic flux formula (e.g., Δϕ=0.60×(0.05×0.025)\Delta\phi = 0.60 \times (0.05 \times 0.025))

1
Q12c
3 marks

Calculate the average EMF induced as the coil is rotated through a quarter turn from a horizontal to a vertical position.

Reveal Answer

ε=nΔϕΔt\varepsilon = n\frac{\Delta\phi}{\Delta t}

ε=20×7.5×1040.0050\varepsilon = 20 \times \frac{7.5 \times 10^{-4}}{0.0050}

ε=3.0 V\varepsilon = 3.0 \text{ V}

Marking Criteria
DescriptorMarks

Calculates the correct time for a quarter turn (Δt=0.0050 s\Delta t = 0.0050 \text{ s})

1

Substitutes values correctly into Faraday's law formula (ε=20×7.5×1040.0050\varepsilon = 20 \times \frac{7.5 \times 10^{-4}}{0.0050})

1

Calculates the correct average EMF of 3.0 V3.0 \text{ V}

1
Q12d
2 marks

State a change to the set-up in Figure 17 that could produce a DC output from the generator. Give a reason for your choice.

Reveal Answer

Replace the slip rings with a split-ring commutator. The split-ring commutator will reverse the connections to the loop every half turn to ensure a DC output.

Marking Criteria
DescriptorMarks

Identifies replacing the slip rings with a split-ring commutator

1

Explains that the split-ring commutator reverses the connections to the loop every half turn to ensure a DC output

1

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