How many NESA Chemistry questions cover Alcohols?

AusGrader has 57 NESA Chemistry questions on Alcohols, all with instant AI grading and detailed marking feedback.

NESA (HSC) Chemistry — Alcohols Questions & Answers | AusGrader

Q10

2023

NESA

1 mark

Q10

1 mark

Which of the following correctly lists the compounds in order of increasing boiling point?

A

Heptane < heptan-2-one < heptan-1-ol < heptanoic acid

B

Heptane < heptan-1-ol < heptan-2-one < heptanoic acid

C

Heptanoic acid < heptan-2-one < heptan-1-ol < heptane

D

Heptanoic acid < heptan-1-ol < heptan-2-one < heptane

Q5

2024

NESA

1 mark

Q5

1 mark

Which would be the best reagent to use to determine whether an unknown substance was 2-methylpropan-1-ol or 2-methylpropan-2-ol?

A

Bromine water

B

Potassium nitrate solution

C

Sodium carbonate solution

D

Acidified potassium permanganate solution

Q27

2023

NESA

4 marks

Q27

4 marks

A student has been asked to produce 185 mL of ethanol ( $MM = 46.068 \text{ g mol}^{-1}$ ) by fermenting glucose using yeast, as shown in the equation.

C_6H_{12}O_6(aq) \rightarrow 2C_2H_5OH(aq) + 2CO_2(g)

Given that the density of ethanol is $0.789 \text{ g mL}^{-1}$ , calculate the volume of carbon dioxide gas produced at 310 K and 100 kPa.

Calculate mass of ethanol required from density

$\rho = \frac{m}{V}$

$m(\text{ethanol}) = 0.789\text{ g mL}^{-1} \times 185\text{ mL} = 146\text{ g}$

$n(\text{ethanol}) = \frac{m}{MM} = \frac{146\text{ g}}{46.068\text{ g mol}^{-1}} = 3.17\text{ mol}$

\begin{align*} V &= \frac{nRT}{P}\\ V &= \frac{3.17\text{ mol} \times 8.314\text{ J K}^{-1}\text{ mol}^{-1} \times 310\text{ K}}{100\text{ kPa}}\\ &= 81.7\text{ L} \end{align*}

Marking Criteria

Descriptor	Marks
Calculates the volume of carbon dioxide produced	4
Provides the main steps of the calculation	3
Provides some steps of the calculation	2
Provides some relevant information	1
None of the above	0

Q37

2025

NESA

4 marks

Q37

4 marks

Compound A has the molecular formula $\text{C}_5\text{H}_{10}$ . The information below shows some chemical reactions beginning with this compound.

Compound A reacts with $\text{H}^+/\text{H}_2\text{O}$ to produce compounds B and C.
Compound B does not react with $\text{H}^+/\text{Cr}_2\text{O}_7^{2-}$ .
Compound C reacts with $\text{H}^+/\text{Cr}_2\text{O}_7^{2-}$ to produce compound D.
Compound D does not react with $\text{Na}_2\text{CO}_3(aq)$ .

Determine the structure of compound A. Justify your answer using all the data given.

Compounds B and C are alkanols.

Compound B cannot be oxidised – so B must be a tertiary alkanol, therefore there must be branching.

Compound C can be oxidised but not to a carboxylic acid (no reaction with carbonate) – so the oxidation product is a ketone, so compound C is a secondary alkanol.

To explain the alkanols produced above, the C=C in compound A is not in the terminal position.

Therefore compound A is 2-methylbut-2-ene (C $_5$ H $_{10}$ ).

Marking Criteria

Descriptor	Marks
Correctly determines the structure of compound A AND Correctly justifies the structure using all the data provided	4
Correctly determines the structure of compound A AND justifies the structure using some of the data provided OR Correctly interprets all of the data provided	3
Correctly interprets some of the data provided	2
Provides some relevant information	1
None of the above	0

Q3

2020

QCAA

Paper 2

9 marks

Q3

Ethanol can be produced by the fermentation of glucose or the hydration of ethene.

Q3a

3 marks

Describe the production of ethanol by fermentation of glucose by writing a balanced equation and indicating if a catalyst is required.

C $_6$ H $_{12}$ O $_6$ (aq) $\xrightarrow{\text{yeast}}$ 2CH $_3$ CH $_2$ OH(aq) + 2CO $_2$ (g)

Marking Criteria

Descriptor	Marks
provides correct reactants and products	1
correctly balances the equation	1
indicates that yeast is required as a catalyst	1

Q3b

2 marks

Calculate the atom economy for the production of ethanol by fermentation of glucose.

Molar mass (ethanol) = 46.08 g
Molar mass (glucose) = 180.18 g
atom economy = $\frac{2 \times 46.08}{180.18} \times 100$

atom economy = $\frac{2 \times 46.08}{180.18} \times 100 = 51.148 \% \approx 51\%$
Atom economy = 51%

Marking Criteria

Descriptor	Marks
shows substitution correctly performed	1
determines atom economy	1

Q3c

2 marks

In terms of atom economy, determine which process for the production of ethanol (i.e. hydration of ethene or fermentation of glucose) is greener.

Hydration atom economy = 100%
Fermentation atom economy = 51%
Therefore, production of ethene by hydration is greener.

Marking Criteria

Descriptor	Marks
determines atom economy for hydration reaction is 100%	1
identifies that hydration reaction is greener	1

Q3d

2 marks

Identify two principles of green chemistry, other than atom economy, that make the production of ethanol by fermentation greener than by hydration.

NESA Chemistry Alcohols

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Descriptor	Marks
provides use of renewable feedstocks	1
provides design for energy efficiency	1