NESA Chemistry Alcohols

15 sample questions with marking guides and sample answers · Avg. score: 65.5%

Q18
2024
VCAA
1 mark
Q18
1 mark

Each of the following compounds has a molar mass of 88 g mol188 \text{ g mol}^{-1}.

Which one has the highest boiling point?

A

CH3CH2OCOCH3\text{CH}_3\text{CH}_2\text{OCOCH}_3

B

CH3(CH2)2COOH\text{CH}_3(\text{CH}_2)_2\text{COOH}

C

CH3(CH2)3CH2OH\text{CH}_3(\text{CH}_2)_3\text{CH}_2\text{OH}

D

CH3NH(CH2)2NHCH3\text{CH}_3\text{NH}(\text{CH}_2)_2\text{NHCH}_3

Reveal Answer
A

CH3CH2OCOCH3\text{CH}_3\text{CH}_2\text{OCOCH}_3

Esters cannot form intermolecular hydrogen bonds, resulting in weaker dipole-dipole interactions and a lower boiling point compared to alcohols and carboxylic acids.

B

CH3(CH2)2COOH\text{CH}_3(\text{CH}_2)_2\text{COOH}

Correct Answer

Carboxylic acids can form strong intermolecular hydrogen bonds, often forming stable dimers. This significantly increases their intermolecular forces and gives them the highest boiling point among compounds of similar molar mass.

C

CH3(CH2)3CH2OH\text{CH}_3(\text{CH}_2)_3\text{CH}_2\text{OH}

While alcohols can form hydrogen bonds, they do not form stable dimers like carboxylic acids do, resulting in slightly weaker overall intermolecular forces and a lower boiling point than option B.

D

CH3NH(CH2)2NHCH3\text{CH}_3\text{NH}(\text{CH}_2)_2\text{NHCH}_3

Amines can form hydrogen bonds, but because nitrogen is less electronegative than oxygen, the N-H bond is less polar than the O-H bond. This makes their hydrogen bonds weaker than those in alcohols and carboxylic acids.

Q18
2020
VCAA
1 mark
Q18
1 mark

An experiment was carried out to determine the enthalpy of combustion of propan-1-ol. Combustion of 557 mg of propan-1-ol increased the temperature of 150 g of water from 22.1C22.1 ^\circ\text{C} to 40.6C40.6 ^\circ\text{C}.

The enthalpy of combustion is closest to

A

2742 kJ mol1-2742 \text{ kJ mol}^{-1}

B

1208 kJ mol1-1208 \text{ kJ mol}^{-1}

C

1250 kJ mol1-1250 \text{ kJ mol}^{-1}

D

1540 kJ mol1-1540 \text{ kJ mol}^{-1}

Reveal Answer
A

2742 kJ mol1-2742 \text{ kJ mol}^{-1}

This answer is incorrect and likely results from a calculation error, such as miscalculating the moles of propan-1-ol or the heat absorbed by the water.

B

1208 kJ mol1-1208 \text{ kJ mol}^{-1}

This answer is incorrect and may result from using an incorrect molar mass for propan-1-ol (C3H8OC_3H_8O, 60.1 g mol160.1 \text{ g mol}^{-1}) or a rounding error early in the calculation.

C

1250 kJ mol1-1250 \text{ kJ mol}^{-1}

Correct Answer

First, calculate the heat absorbed by water: q=mcΔT=150×4.18×18.5=11.6 kJq = mc\Delta T = 150 \times 4.18 \times 18.5 = 11.6 \text{ kJ}. Then, divide by the moles of propan-1-ol (0.557 g/60.1 g mol1=0.00927 mol0.557 \text{ g} / 60.1 \text{ g mol}^{-1} = 0.00927 \text{ mol}) to get 1251 kJ mol1-1251 \text{ kJ mol}^{-1}, which is closest to 1250 kJ mol1-1250 \text{ kJ mol}^{-1}.

D

1540 kJ mol1-1540 \text{ kJ mol}^{-1}

This answer is incorrect and likely stems from an error in calculating the temperature change (ΔT=18.5C\Delta T = 18.5 ^\circ\text{C}) or the heat energy transferred.

Q22
2023
VCAA
1 mark
Q22
1 mark

Methane, CH4\text{CH}_4, and methanol, CH3OH\text{CH}_3\text{OH}, can both be used to power fuel cells.

Methane and methanol fuel cells produce

A

the same amount of greenhouse gases and the same number of electrons per mol of fuel reacted.

B

the same amount of greenhouse gases and a different number of electrons per mol of fuel reacted.

C

a different amount of greenhouse gases and the same number of electrons per mol of fuel reacted.

D

a different amount of greenhouse gases and a different number of electrons per mol of fuel reacted.

Reveal Answer
A

the same amount of greenhouse gases and the same number of electrons per mol of fuel reacted.

While both fuels produce the same amount of greenhouse gases (1 mole of CO2\text{CO}_2 per mole of fuel), they produce a different number of electrons during oxidation.

B

the same amount of greenhouse gases and a different number of electrons per mol of fuel reacted.

Correct Answer

Both fuels contain one carbon atom per molecule, producing 1 mole of CO2\text{CO}_2 per mole of fuel. However, the oxidation state of carbon changes by 8 in methane and 6 in methanol, producing a different number of electrons.

C

a different amount of greenhouse gases and the same number of electrons per mol of fuel reacted.

This is incorrect because they produce the same amount of greenhouse gases (1 mole of CO2\text{CO}_2 per mole of fuel) and a different number of electrons.

D

a different amount of greenhouse gases and a different number of electrons per mol of fuel reacted.

This is incorrect because they produce the same amount of greenhouse gases, as both fuels contain exactly one carbon atom per molecule and thus yield the same amount of CO2\text{CO}_2.

Q4
2022
QCAA
Paper 2
8 marks
Q4

Bioethanol is a renewable energy source made from biomasses such as starch and cellulosic materials. The two-step process for the conversion of starch and cellulose to bioethanol is shown.

ProcessStep 1Step 2Conversion to glucoseProduction process
StarchEnzymatic hydrolysis (α\alpha-amylase) of starch biomass to form glucoseFermentation of glucose to form bioethanol (yeast)EasierFaster
CelluloseAcid hydrolysis (H2SO4(aq)H_2SO_4(aq) at 320 ^{\circ}C and 25 MPa) of cellulose biomass to form glucoseFermentation of glucose to form bioethanol (yeast)HarderSlower
Q4a
2 marks

Identify why it is important to control the temperature during the fermentation process to produce bioethanol.

Reveal Answer

The fermentation process requires yeast as a catalyst.
Yeast is temperature sensitive.

Marking Criteria
DescriptorMarks

Identifies fermentation requires yeast as a catalyst

1

Identifies that yeast is temperature-sensitive

1
Q4b
3 marks

Explain why cellulose is harder to convert to glucose than starch.

Reveal Answer

Cellulose is a linear polymer. The β\beta-glucose monomers in cellulose can pack closely together. This increases hydrogen bonding between adjacent chains, which reduces interactions with water (solvents) and makes hydrolysis of cellulose more difficult than starch.

Marking Criteria
DescriptorMarks

Identifies cellulose is a linear polymer

1

Identifies monomers can pack closely together

1

Explains increased H-bonding between adjacent chains makes hydrolysis of cellulose more difficult

1
Q4c
3 marks

After 48 hours of fermentation, a 15% w/v glucose solution produces 37.5 g L137.5\ \text{g L}^{-1} of ethanol. Calculate the percentage yield of ethanol. Show your working. (to one decimal place)

Reveal Answer

Moles C6H12O6=150180.18=0.833C_6H_{12}O_6 = \frac{150}{180.18} = 0.833

Moles CH3CH2OH=0.83×2=1.67CH_3CH_2OH = 0.83 \times 2 = 1.67

Mass CH3CH2OH=1.67×46.08=76.72CH_3CH_2OH = 1.67 \times 46.08 = 76.72 g

Ethanol yield = 37.5theoretical yield=37.576.72=48.9%\frac{37.5}{\text{theoretical yield}} = \frac{37.5}{76.72} = 48.9\%

Marking Criteria
DescriptorMarks

Determines 150 g glucose can produce 1.67 M of ethanol

1

Calculates theoretical mass of ethanol as 76.72 g

1

Calculates % yield of ethanol is 48.9%

1
Q21
2024
SCSA
1 mark
Q21
1 mark

Which of the following is not a product of the oxidation of pentan-1-ol?

A

CH3CH2CH2CH2CHOCH_3CH_2CH_2CH_2CHO

B

CO2CO_2

C

CH3CH2CH2COCH3CH_3CH_2CH_2COCH_3

D

CH3CH2CH2CH2COOHCH_3CH_2CH_2CH_2COOH

Reveal Answer
A

CH3CH2CH2CH2CHOCH_3CH_2CH_2CH_2CHO

Pentanal (CH3CH2CH2CH2CHOCH_3CH_2CH_2CH_2CHO) is a valid product formed by the partial oxidation of pentan-1-ol, which is a primary alcohol.

B

CO2CO_2

Carbon dioxide (CO2CO_2) is a valid product of the complete oxidation (combustion) of pentan-1-ol.

C

CH3CH2CH2COCH3CH_3CH_2CH_2COCH_3

Correct Answer

Pentan-2-one (CH3CH2CH2COCH3CH_3CH_2CH_2COCH_3) is a ketone, which is produced by the oxidation of a secondary alcohol (like pentan-2-ol), not a primary alcohol like pentan-1-ol.

D

CH3CH2CH2CH2COOHCH_3CH_2CH_2CH_2COOH

Pentanoic acid (CH3CH2CH2CH2COOHCH_3CH_2CH_2CH_2COOH) is a valid product formed by the full oxidation of pentan-1-ol using a strong oxidizing agent.

Q2
2021
VCAA
1 mark
Q2
1 mark

Biodiesel and petrodiesel

A

have different viscosities.

B

have the same environmental impact.

C

contain molecules with no polar groups.

D

will flow easily through fuel lines in very cold climate conditions.

Reveal Answer
A

have different viscosities.

Correct Answer

This is correct because biodiesel contains polar ester groups that create stronger intermolecular forces, resulting in a higher viscosity compared to non-polar petrodiesel.

B

have the same environmental impact.

This is incorrect because biodiesel is derived from renewable biomass and generally produces fewer net carbon emissions and particulates compared to fossil-fuel-derived petrodiesel.

C

contain molecules with no polar groups.

This is incorrect because while petrodiesel consists of non-polar hydrocarbons, biodiesel consists of fatty acid methyl esters which contain polar ester groups.

D

will flow easily through fuel lines in very cold climate conditions.

This is incorrect because biodiesel has a higher cloud point than petrodiesel, meaning it is more prone to gelling and restricting flow in very cold climates.

Q25
2024
VCAA
1 mark
Q25
1 mark

Use the following information to answer the question.

A chemist runs a mixture of hexane, hexan-1-ol and hexan-2-one through a high-performance liquid chromatography (HPLC) column using a polar mobile phase and a non-polar stationary phase.

Which of the following shows the chemicals in order of their retention times, from lowest to highest?

A

hexane, hexan-2-one, hexan-1-ol

B

hexane, hexan-1-ol, hexan-2-one

C

hexan-2-one, hexan-1-ol, hexane

D

hexan-1-ol, hexan-2-one, hexane

Reveal Answer
A

hexane, hexan-2-one, hexan-1-ol

This order represents the highest to lowest retention time, which would be the correct order if the stationary phase were polar (normal-phase HPLC).

B

hexane, hexan-1-ol, hexan-2-one

Hexane is the most non-polar compound, meaning it will interact most strongly with the non-polar stationary phase and have the highest, not lowest, retention time.

C

hexan-2-one, hexan-1-ol, hexane

While hexane correctly has the highest retention time, hexan-1-ol is more polar than hexan-2-one due to its ability to form hydrogen bonds, so hexan-1-ol will elute before hexan-2-one.

D

hexan-1-ol, hexan-2-one, hexane

Correct Answer

In reverse-phase HPLC (non-polar stationary phase, polar mobile phase), the most polar compound has the lowest retention time. Hexan-1-ol (most polar) elutes first, followed by hexan-2-one, and the non-polar hexane elutes last.

Q3
2022
VCAA
1 mark
Q3
1 mark

The correct equation for the incomplete combustion of ethanol is

A

C2H5OH(l)+12O2(g)2CO(g)+3H2(g)\text{C}_2\text{H}_5\text{OH(l)} + \frac{1}{2}\text{O}_2\text{(g)} \rightarrow 2\text{CO(g)} + 3\text{H}_2\text{(g)}

B

C2H5OH(l)+32O2(g)2CO2(g)+3H2(g)\text{C}_2\text{H}_5\text{OH(l)} + \frac{3}{2}\text{O}_2\text{(g)} \rightarrow 2\text{CO}_2\text{(g)} + 3\text{H}_2\text{(g)}

C

C2H5OH(l)+2O2(g)2CO(g)+3H2O(l)\text{C}_2\text{H}_5\text{OH(l)} + 2\text{O}_2\text{(g)} \rightarrow 2\text{CO(g)} + 3\text{H}_2\text{O(l)}

D

C2H5OH(l)+3O2(g)2CO2(g)+3H2O(l)\text{C}_2\text{H}_5\text{OH(l)} + 3\text{O}_2\text{(g)} \rightarrow 2\text{CO}_2\text{(g)} + 3\text{H}_2\text{O(l)}

Reveal Answer
A

C2H5OH(l)+12O2(g)2CO(g)+3H2(g)\text{C}_2\text{H}_5\text{OH(l)} + \frac{1}{2}\text{O}_2\text{(g)} \rightarrow 2\text{CO(g)} + 3\text{H}_2\text{(g)}

This equation is incorrect because combustion reactions of hydrocarbons and alcohols produce water (H2O\text{H}_2\text{O}), not hydrogen gas (H2\text{H}_2).

B

C2H5OH(l)+32O2(g)2CO2(g)+3H2(g)\text{C}_2\text{H}_5\text{OH(l)} + \frac{3}{2}\text{O}_2\text{(g)} \rightarrow 2\text{CO}_2\text{(g)} + 3\text{H}_2\text{(g)}

This equation is incorrect because it produces carbon dioxide (CO2\text{CO}_2), which is a product of complete combustion, and hydrogen gas (H2\text{H}_2) instead of water.

C

C2H5OH(l)+2O2(g)2CO(g)+3H2O(l)\text{C}_2\text{H}_5\text{OH(l)} + 2\text{O}_2\text{(g)} \rightarrow 2\text{CO(g)} + 3\text{H}_2\text{O(l)}

Correct Answer

This is correct because the incomplete combustion of ethanol produces carbon monoxide (CO\text{CO}) and water (H2O\text{H}_2\text{O}), and this chemical equation is properly balanced.

D

C2H5OH(l)+3O2(g)2CO2(g)+3H2O(l)\text{C}_2\text{H}_5\text{OH(l)} + 3\text{O}_2\text{(g)} \rightarrow 2\text{CO}_2\text{(g)} + 3\text{H}_2\text{O(l)}

This equation represents the complete combustion of ethanol, which produces carbon dioxide (CO2\text{CO}_2) rather than the carbon monoxide (CO\text{CO}) produced during incomplete combustion.

Q25
2025
VCAA
1 mark
Q25
1 mark

During fermentation, yeast will produce other volatile polar compounds that have similar boiling points to ethanol, C2H6OC_2H_6O.

Which one of the following methods would be most suitable to separate these compounds from C2H6OC_2H_6O?

A

solvent extraction

B

simple distillation

C

fractional distillation

D

solvent extraction and distillation

Reveal Answer
A

solvent extraction

Solvent extraction relies on differences in solubility, which would likely be ineffective here since both ethanol and the other compounds are polar and may dissolve in similar solvents.

B

simple distillation

Simple distillation is only effective for separating liquids with significantly different boiling points (typically a difference of at least 25°C).

C

fractional distillation

Correct Answer

Fractional distillation is specifically designed to separate miscible volatile liquids that have very similar boiling points.

D

solvent extraction and distillation

Adding solvent extraction is unnecessary and less efficient, as fractional distillation alone is the standard and most effective method for separating liquids with similar boiling points.

Q14
2024
QCAA
Paper 1
1 mark
Q14
1 mark

The question refers to the reactions below.

Reaction 1: CH3CH2OHH+/Cr2O72(heat/reflux)compound X\text{CH}_3\text{CH}_2\text{OH} \xrightarrow{\text{H}^+/\text{Cr}_2\text{O}_7^{2-} (\text{heat/reflux})} \text{compound X}

Reaction 2: compound X+CH3NH2TiCl4(heat>100C)compound Y\text{compound X} + \text{CH}_3\text{NH}_2 \xrightarrow{\text{TiCl}_4 (\text{heat} > 100^\circ\text{C})} \text{compound Y}

Identify compound Y.

A

CH3_3CH2_2CN

B

CH3_3CONHCH3_3

C

CH3_3CH2_2CH2_2NH2_2

D

H2_2NCH(CH3_3)COOH

Reveal Answer
A

CH3_3CH2_2CN

This is a nitrile (propanenitrile). Nitriles are typically synthesized by reacting haloalkanes with cyanide ions, not by reacting oxidation products of alcohols with amines.

B

CH3_3CONHCH3_3

Correct Answer

Reaction 1 oxidizes ethanol to ethanoic acid (CH3extCOOH\text{CH}_3 ext{COOH}) under reflux. Reaction 2 is a condensation reaction where the carboxylic acid reacts with methylamine (CH3extNH2\text{CH}_3 ext{NH}_2) under heat to form an amide, N-methylethanamide.

C

CH3_3CH2_2CH2_2NH2_2

This is a primary amine with three carbons. The reaction sequence does not add carbon atoms to the chain, nor does it reduce a functional group to a primary amine.

D

H2_2NCH(CH3_3)COOH

This is an amino acid (alanine). The reaction produces a simple amide from a carboxylic acid and an amine, not a molecule with both amine and carboxylic acid functional groups on the same carbon.

Q22
2024
VCAA
1 mark
Q22
1 mark

Use the following information to answer the question.

A triglyceride is reacted with methanol, CH3OH\text{CH}_3\text{OH}, in the presence of concentrated KOH(aq)\text{KOH}(\text{aq}). The products of this reaction are glycerol and Compound J.

The molecular formula of Compound J is C19H30O2\text{C}_{19}\text{H}_{30}\text{O}_2.

What is the molecular formula of the triglyceride?

A

C54H82O3\text{C}_{54}\text{H}_{82}\text{O}_3

B

C54H82O6\text{C}_{54}\text{H}_{82}\text{O}_6

C

C57H84O3\text{C}_{57}\text{H}_{84}\text{O}_3

D

C57H86O6\text{C}_{57}\text{H}_{86}\text{O}_6

Reveal Answer
A

C54H82O3\text{C}_{54}\text{H}_{82}\text{O}_3

This formula is incorrect because a triglyceride must contain 6 oxygen atoms, not 3, and the carbon and hydrogen counts do not balance the transesterification reaction.

B

C54H82O6\text{C}_{54}\text{H}_{82}\text{O}_6

This formula is incorrect because it fails to account for the 3 carbon atoms from the glycerol backbone, resulting in 54 carbons instead of 57.

C

C57H84O3\text{C}_{57}\text{H}_{84}\text{O}_3

This formula is incorrect because a triglyceride contains 3 ester groups, meaning it must have 6 oxygen atoms, not 3.

D

C57H86O6\text{C}_{57}\text{H}_{86}\text{O}_6

Correct Answer

This is correct. In the transesterification reaction, 1 Triglyceride + 3 Methanol (CH4O\text{CH}_4\text{O}) \rightarrow 1 Glycerol (C3H8O3\text{C}_3\text{H}_8\text{O}_3) + 3 Compound J (C19H30O2\text{C}_{19}\text{H}_{30}\text{O}_2). Balancing the atoms yields C57H86O6\text{C}_{57}\text{H}_{86}\text{O}_6.

Q33
2021
SCSA
8 marks
Q33
8 marks

Ethanol (C2H5OHC_2H_5OH) dissolves readily in water, while decan-1-ol (C10H21OHC_{10}H_{21}OH) has very limited solubility. Explain, with the aid of labelled diagrams, why ethanol is able to dissolve in water and decan-1-ol is not.

Reveal Answer

In order for a solute to dissolve in a solvent the energy released in the formation of the intermolecular forces between the solute and solvent are sufficient to overcome the existing intermolecular forces between the solute molecules and the solvent molecules.

Both alcohols form dispersion forces and hydrogen bonds with water.

Ethanol and water both have hydrogen bonding as their predominant type of intermolecular force.

The energy required to disrupt the hydrogen bonds in the ethanol and water are comparable to the energy released during the formation of the hydrogen bonds between the ethanol and water molecules and so dissolution occurs.

The predominant type of intermolecular force in decan-1-ol is dispersion forces.

The energy released during the formation of dispersion forces with water and decan-1-ol is not sufficient to disrupt the dispersion forces between the decan-1-ol molecules and so dissolving does not occur.

Diagrams can include:

  • Diagram showing the hydrogen bonding between the ethanol and water molecules.
  • Diagram showing the dispersion forces between decan-1-ol.
Marking Criteria

Response

DescriptorMarks

A detailed, coherent response consisting of the majority of the points below (up to 6 marks):
• In order for a solute to dissolve in a solvent the energy released in the formation of the intermolecular forces between the solute and solvent are sufficient to overcome the existing intermolecular forces between the solute molecules and the solvent molecules.
• Both alcohols form dispersion forces and hydrogen bonds with water.
• Ethanol and water both have hydrogen bonding as their predominant type of intermolecular force.
• The energy required to disrupt the hydrogen bonds in the ethanol and water are comparable to the energy released during the formation of the hydrogen bonds between the ethanol and water molecules and so dissolution occurs.
• The predominant type of intermolecular force in decan-1-ol is dispersion forces.
• The energy released during the formation of dispersion forces with water and decan-1-ol is not sufficient to disrupt the dispersion forces between the decan-1-ol molecules and so dissolving does not occur.

6

Diagrams

DescriptorMarks

1 mark for each appropriate labelled diagram showing interactions between solute and solvent (up to 2 marks), for example:

  • Diagram showing the hydrogen bonding between the ethanol and water molecules.
  • Diagram showing the dispersion forces between decan-1-ol.
2
Q22
2022
SCSA
1 mark
Q22
1 mark

How many moles of oxygen will be consumed in the complete combustion of 1 mole of ethanol? The unbalanced equation for this reaction is shown below.

C2H6O()+O2(g)CO2(g)+H2O(g)\mathrm{C_2H_6O(\ell)} + \mathrm{O_2(g)} \rightarrow \mathrm{CO_2(g)} + \mathrm{H_2O(g)}
A

1 mol

B

2 mol

C

3 mol

D

4 mol

Reveal Answer
A

1 mol

This is incorrect. Using 1 mole of O2\mathrm{O_2} would only provide 3 oxygen atoms on the reactant side, which is not enough to balance the carbon and hydrogen atoms in the products.

B

2 mol

This is incorrect. Using 2 moles of O2\mathrm{O_2} provides 5 oxygen atoms on the reactant side, which is insufficient to form the required 2CO22\mathrm{CO_2} and 3H2O3\mathrm{H_2O} molecules.

C

3 mol

Correct Answer

This is correct. The balanced equation is C2H6O+3O22CO2+3H2O\mathrm{C_2H_6O} + 3\mathrm{O_2} \rightarrow 2\mathrm{CO_2} + 3\mathrm{H_2O}, which shows that exactly 3 moles of oxygen gas are required to completely combust 1 mole of ethanol.

D

4 mol

This is incorrect. Using 4 moles of O2\mathrm{O_2} would result in 9 oxygen atoms on the reactant side, which is more than the 7 oxygen atoms needed for the products.

Q19
2021
QCAA
Paper 1
1 mark
Q19
1 mark

To form ethanol biofuel in the fermentation of glucose, a catalyst is used because

A

less energy is required and the rate of reaction is increased.

B

less energy is required and the rate of reaction is decreased.

C

more energy is required and the rate of reaction is increased.

D

more energy is required and the rate of reaction is decreased.

Reveal Answer
A

less energy is required and the rate of reaction is increased.

Correct Answer

Catalysts (such as the enzymes in yeast) provide an alternative reaction pathway with a lower activation energy, which allows the reaction to proceed faster.

B

less energy is required and the rate of reaction is decreased.

While catalysts do lower the activation energy required, they function to speed up the reaction, not slow it down.

C

more energy is required and the rate of reaction is increased.

Catalysts lower the activation energy required for the reaction to occur, rather than requiring more energy.

D

more energy is required and the rate of reaction is decreased.

This is incorrect because catalysts lower the activation energy and increase the rate of reaction.

Q5
2024
NESA
1 mark
Q5
1 mark

Which would be the best reagent to use to determine whether an unknown substance was 2-methylpropan-1-ol or 2-methylpropan-2-ol?

A

Bromine water

B

Potassium nitrate solution

C

Sodium carbonate solution

D

Acidified potassium permanganate solution

Reveal Answer
A

Bromine water

Bromine water is used to test for the presence of carbon-carbon double bonds (unsaturation). It would not react with either of these saturated alcohols.

B

Potassium nitrate solution

Potassium nitrate is generally unreactive with alcohols and would not produce a visible change to help distinguish between the two substances.

C

Sodium carbonate solution

Sodium carbonate is typically used to test for acidic substances like carboxylic acids by observing effervescence (carbon dioxide gas), but it does not react with alcohols.

D

Acidified potassium permanganate solution

Correct Answer

Acidified potassium permanganate is a strong oxidizing agent. It will oxidize the primary alcohol (2-methylpropan-1-ol), changing color from purple to colorless, but will not react with the tertiary alcohol (2-methylpropan-2-ol).

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