NESA Biology Processing Data and Information

Qualitative data is descriptive and non-numerical, meaning it is not possible to calculate a mathematical average from it.

Qualitative data consists of descriptions, characteristics, or categories, rather than numerical values.

Measuring the wavelength of light produces numerical values with units, which is an example of quantitative data, not qualitative.

While larger animals do have a lower surface area to volume ratio, this actually makes them less susceptible to heat loss, not more.

Larger animals have a lower, not higher, surface area to volume ratio because volume increases cubically while surface area only increases quadratically.

Larger animals have a lower surface area to volume ratio, not higher. Additionally, a higher ratio would make an animal more susceptible to heat loss.

Obtaining data from other students' investigations is an example of collecting secondary data, not primary data.

Recording the smell of insecticides generates qualitative data (descriptive), not quantitative data (numerical).

Reading newspaper articles is a method of gathering secondary data, as the information was collected and published by someone else.

Community I has a species richness of 5 (species E is absent), which is lower than communities III and IV. Additionally, it has low evenness because the population is dominated by species F and A.

Community II has a species richness of 5 (species C is absent), which is lower than the maximum richness observed in other communities. It also shows low evenness due to the dominance of species F.

Although Community III has the highest species richness (6 species), it has low evenness. The abundance is skewed heavily toward species F (51) and C (28), while other species have very low counts.

The number of days is a numerical count, making this quantitative discrete data rather than qualitative data.

The average number of hours is a numerical measurement, which represents quantitative continuous data, not qualitative data.

Mean monthly precipitation is a numerical measurement, making it quantitative continuous data rather than qualitative data.

This value is incorrect. It results from miscalculating the net change or using the wrong denominator in the growth rate formula.

This calculation incorrectly considers only the population inputs (Births + Immigration) divided by the initial population ($\frac{8390}{15\,200} \approx 55\%$), failing to subtract deaths and emigration.

This option is incorrect and likely represents the complement of the correct answer ($100\% - 27\% = 73\%$), rather than the actual growth rate.

The concentration of carbon dioxide is a measurable, numerical value, making it quantitative data rather than qualitative.

The number of chlorophyll molecules is a countable, numerical value, which represents quantitative data.

The mass of minerals is a measurable, numerical value, making it quantitative data.

Incorrect. The treatment requires 14 tablets (2 per day for 7 days). At a rate of ＄25.00 per 28 tablets, the total cost is ＄12.50, which is not the lowest.

Incorrect. The treatment requires 56 tablets (4 per day for 14 days). At a rate of ＄30.00 per 100 tablets, the total cost is ＄16.80, making it the most expensive option.

Incorrect. The treatment requires 10 tablets (2 per day for 5 days). At a rate of ＄25.00 per 28 tablets, the total cost is approximately ＄8.93.

This answer results from incorrectly swapping the values for the total captured in the second sample ($n$) and the marked recaptures ($m$) in the formula ($N = \frac{36 \times 18}{24} = 27$).

This incorrect value likely results from simply adding the number of initially marked frogs to the number of marked frogs found in the second sample ($36 + 18 = 54$).

This incorrect value results from adding the number of initially marked frogs to the total number of frogs captured in the second sample ($36 + 24 = 60$) instead of using the multiplication and division required by the formula.

This answer is incorrect. It does not match the result derived from dividing the net population change by the initial population.

This value is incorrect. It is very close to the birth rate ($\frac{290}{1100} \approx 26.4\%$), which fails to account for deaths, immigration, and emigration.

This represents the ratio of the initial population to the final population ($\frac{1100}{1265} \approx 86.9\%$), rather than the percentage of growth.

This incorrect answer results from dividing the mass by the conversion factor and failing to convert kilograms to grams ($36 \div 1.12$).

This incorrect answer results from multiplying the mass by the conversion factor without converting kilograms to grams ($36 \times 1.12$).

This incorrect answer results from correctly converting kilograms to grams but dividing by the conversion factor instead of multiplying ($36,000 \div 1.12$).

Incorrect. The value 0.25 represents the proportion of offspring that inherit two copies of the lethal yellow allele and die before birth, not the proportion of surviving yellow offspring.

Incorrect. The value 0.33 (or 1/3) is the expected proportion of surviving offspring that have non-yellow fur, rather than yellow fur.

Incorrect. A proportion of 0.50 would be expected from a cross between a heterozygous yellow individual and a homozygous non-yellow individual, not a cross between two heterozygotes.

This is the fourth value when the temperatures are ordered from lowest to highest. Since there is an even number of data points, the median must be the average of the two middle values.

This value represents the mean (average) of the body temperatures, not the median. The mean is calculated by adding all values and dividing by 6.

This is the third value when the temperatures are ordered. The median requires averaging the third and fourth values since there are six data points.